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Q.a position dependent force,F= (7-2x+3x^2)N acts on a small body of mass 2 kg and displaces it from x= 0 to x= 5 m.The work done in joules is
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Q.a position dependent force,F= (7-2x+3x^2)N acts on a small body of m...
sorry its 107 J ...just integrate force with dx and limit is from 0 to 5 m
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Q.a position dependent force,F= (7-2x+3x^2)N acts on a small body of m...
7-2x+3x^2.dx[7-2x^2/2+3x^3/3][7-5^2+5^3]=107J
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Q.a position dependent force,F= (7-2x+3x^2)N acts on a small body of mass 2 kg and displaces it from x= 0 to x= 5 m.The work done in joules is
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