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A student is standing with a banner at the top of a 100 m high college building. From a point on the ground, the angle of elevation of the top of the student is 60° and from the same point, the angle of elevation of the top of the tower is 45°. Find the height of the student.
  • a)
    35 m
  • b)
    73.2 m
  • c)
    50 m
  • d)
    75m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A student is standing with a banner at the top of a 100 m high college...
Let BC be the height of the tower and DC be the height of the student.
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Most Upvoted Answer
A student is standing with a banner at the top of a 100 m high college...
Degrees. What is the distance between the student and the point on the ground?

We can use trigonometry to solve this problem. Let's call the distance between the student and the point on the ground "x". We can then use the tangent function, which relates the opposite (the height of the building) to the adjacent (the distance between the student and the point on the ground):

tan(60) = opposite/adjacent
tan(60) = 100/x

We can solve for x by multiplying both sides by x and then dividing by tan(60):

x = 100 / tan(60)
x = 100 / 1.732
x ≈ 57.74 meters

Therefore, the distance between the student and the point on the ground is approximately 57.74 meters.
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Community Answer
A student is standing with a banner at the top of a 100 m high college...
73.2 is the correct answer.
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A student is standing with a banner at the top of a 100 m high college building. From a point on the ground, the angle of elevation of the top of the student is 60° and from the same point, the angle of elevation of the top of the tower is 45°. Find the height of the student.a)35 mb)73.2 mc)50 md)75mCorrect answer is option 'B'. Can you explain this answer?
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