Which contains greater number of oxygen atoms? (a) 1gm of O (b) 1 gm o...
Explanation:
All the options given in the question contain oxygen atoms but in different molecular forms. Let's analyze each option and calculate the number of oxygen atoms present in each of them.
(a) 1 gram of O: Here, O represents a single oxygen atom. So, 1 gram of O contains 6.022 x 10^23 oxygen atoms (Avogadro's number).
(b) 1 gram of O2: Here, O2 represents a molecule of oxygen that contains two oxygen atoms. So, 1 gram of O2 contains 1/32 moles of O2 (molar mass of O2 = 32 g/mol) which is equal to 1/32 x 6.022 x 10^23 = 1.88 x 10^21 oxygen atoms.
(c) 1 gram of O3: Here, O3 represents a molecule of ozone that contains three oxygen atoms. So, 1 gram of O3 contains 1/48 moles of O3 (molar mass of O3 = 48 g/mol) which is equal to 1/48 x 6.022 x 10^23 = 1.25 x 10^21 oxygen atoms.
(d) All have the same number of oxygen atoms: From the above calculations, we can see that 1 gram of O contains the same number of oxygen atoms as 1 gram of O2 and 1 gram of O3. This is because the number of oxygen atoms is determined by the Avogadro's number which is a constant and does not depend on the molecular form of oxygen.
Therefore, the correct answer is (d) all have the same number of oxygen atoms.
Which contains greater number of oxygen atoms? (a) 1gm of O (b) 1 gm o...
A) No.of atoms =n x atomicity x N
1/16x1xN=N/16
b) =N/32x2=N/16
c) =N/48x3=N/16
so d option is correct
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