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An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it?
Most Upvoted Answer
An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500...
The resistance of electric iron is the equivalent of the above three appliances.. i.e,
1/Rₑ = 1/R₁ + 1/R₂ + 1/R₃ = 1/100 + 1/50+ 1/500
By solving it, you will get ....
Rₑ = 500/16 Ω
now, V = IR
So, I = 220/(500/16) = 7.04 A
1/Rₑ = 1/R₁ + 1/R₂ + 1/R₃ = 1/100 + 1/50+ 1/500
By solving it, you will get ....
Rₑ = 500/16 Ω
now, V = IR
So, I = 220/(500/16) = 7.04 A
Community Answer
An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500...
Calculating the current through the appliances:
To find the current through each appliance, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.
For the electric lamp:
Using Ohm's Law, the current through the lamp can be calculated as:
I_lamp = V / R_lamp = 220V / 100Ω = 2.2A
For the toaster:
Using Ohm's Law, the current through the toaster can be calculated as:
I_toaster = V / R_toaster = 220V / 50Ω = 4.4A
For the water filter:
Using Ohm's Law, the current through the water filter can be calculated as:
I_filter = V / R_filter = 220V / 500Ω = 0.44A
Calculating the equivalent resistance of the parallel connection:
When resistors are connected in parallel, the total resistance (R_total) can be calculated using the formula:
1 / R_total = 1 / R1 + 1 / R2 + 1 / R3 + ...
In this case, we have three resistors connected in parallel, so the formula becomes:
1 / R_total = 1 / R_lamp + 1 / R_toaster + 1 / R_filter
Substituting the values:
1 / R_total = 1 / 100Ω + 1 / 50Ω + 1 / 500Ω
Simplifying the equation:
1 / R_total = 0.01 + 0.02 + 0.002
1 / R_total = 0.032
R_total = 1 / 0.032
R_total = 31.25Ω
Calculating the resistance and current through the electric iron:
Since the electric iron is connected in parallel with the other appliances, it will have the same voltage (V) as the source. To find the resistance of the electric iron (R_iron), we can use Ohm's Law:
R_iron = V / I_total
Substituting the values:
R_iron = 220V / (2.2A + 4.4A + 0.44A)
R_iron = 220V / 7.04A
R_iron ≈ 31.25Ω
The resistance of the electric iron is approximately 31.25Ω.
To find the current through the electric iron (I_iron), we can use Ohm's Law:
I_iron = V / R_iron
Substituting the values:
I_iron = 220V / 31.25Ω
I_iron ≈ 7.04A
The current through the electric iron is approximately 7.04A.
To find the current through each appliance, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.
For the electric lamp:
Using Ohm's Law, the current through the lamp can be calculated as:
I_lamp = V / R_lamp = 220V / 100Ω = 2.2A
For the toaster:
Using Ohm's Law, the current through the toaster can be calculated as:
I_toaster = V / R_toaster = 220V / 50Ω = 4.4A
For the water filter:
Using Ohm's Law, the current through the water filter can be calculated as:
I_filter = V / R_filter = 220V / 500Ω = 0.44A
Calculating the equivalent resistance of the parallel connection:
When resistors are connected in parallel, the total resistance (R_total) can be calculated using the formula:
1 / R_total = 1 / R1 + 1 / R2 + 1 / R3 + ...
In this case, we have three resistors connected in parallel, so the formula becomes:
1 / R_total = 1 / R_lamp + 1 / R_toaster + 1 / R_filter
Substituting the values:
1 / R_total = 1 / 100Ω + 1 / 50Ω + 1 / 500Ω
Simplifying the equation:
1 / R_total = 0.01 + 0.02 + 0.002
1 / R_total = 0.032
R_total = 1 / 0.032
R_total = 31.25Ω
Calculating the resistance and current through the electric iron:
Since the electric iron is connected in parallel with the other appliances, it will have the same voltage (V) as the source. To find the resistance of the electric iron (R_iron), we can use Ohm's Law:
R_iron = V / I_total
Substituting the values:
R_iron = 220V / (2.2A + 4.4A + 0.44A)
R_iron = 220V / 7.04A
R_iron ≈ 31.25Ω
The resistance of the electric iron is approximately 31.25Ω.
To find the current through the electric iron (I_iron), we can use Ohm's Law:
I_iron = V / R_iron
Substituting the values:
I_iron = 220V / 31.25Ω
I_iron ≈ 7.04A
The current through the electric iron is approximately 7.04A.
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An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it?
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An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it?.
An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electric lamp of 100ohm, a toaster of 50 ohm and a water filter 500ohm are connected in parallel to a 220V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances and what is the current through it?.
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