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If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ?
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If momentum P and velocity v are related as P=√a\b v2 then dimensional...
Preliminary Information:
- Momentum (P) is defined as the product of mass (m) and velocity (v), i.e., P = mv.
- The dimensional formula for momentum is [MLT^-1].
Given:
P = √(a\b) * v^2
To find:
Dimensional formula of [ab^-2]
Solution:
We are given that P = √(a\b) * v^2
Squaring both sides, we get:
P^2 = (a\b) * v^4
Comparing the dimensions on both sides of the equation:
Left side: [MLT^-1]^2 = [M^2L^2T^-2]
Right side: (a\b) * [LT^-1]^4 = (a\b) * [L^4T^-4]
As the dimensions on both sides must be equal, we can equate the exponents of mass, length, and time:
Mass dimension: 2 = a
Length dimension: 2 = -b + 4
Time dimension: -2 = -4
Solving the equations, we get:
a = 2
b = -2
Therefore, the dimensional formula of [ab^-2] is [M^2L^2T^-2], which corresponds to option (3) [M2L2T^-2].
Conclusion:
The dimensional formula of [ab^-2] is [M2L2T^-2].
- Momentum (P) is defined as the product of mass (m) and velocity (v), i.e., P = mv.
- The dimensional formula for momentum is [MLT^-1].
Given:
P = √(a\b) * v^2
To find:
Dimensional formula of [ab^-2]
Solution:
We are given that P = √(a\b) * v^2
Squaring both sides, we get:
P^2 = (a\b) * v^4
Comparing the dimensions on both sides of the equation:
Left side: [MLT^-1]^2 = [M^2L^2T^-2]
Right side: (a\b) * [LT^-1]^4 = (a\b) * [L^4T^-4]
As the dimensions on both sides must be equal, we can equate the exponents of mass, length, and time:
Mass dimension: 2 = a
Length dimension: 2 = -b + 4
Time dimension: -2 = -4
Solving the equations, we get:
a = 2
b = -2
Therefore, the dimensional formula of [ab^-2] is [M^2L^2T^-2], which corresponds to option (3) [M2L2T^-2].
Conclusion:
The dimensional formula of [ab^-2] is [M2L2T^-2].
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If momentum P and velocity v are related as P=√a\b v2 then dimensional...
Question is not cleared Yeh under root a and b per hai kya
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If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ?
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If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ?.
If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If momentum P and velocity v are related as P=√a\b v2 then dimensional formula of [ab-2] is (1) [MLT-1] (2)[M2L2T-1] (3)[M2L2T-2] (4)[ML2T-2] Answer is (3) Anyone please explain me ?.
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