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Let n(A) denotes the number of elements in set A. If n(A) =p and n(B) = q, then how many ordered pairs (a, b) are there with a ∈ A and b ∈ B ?
  • a)
    p2
  • b)
    p x q
  • c)
    p + q
  • d)
    2 pq
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Let n(A) denotes the number of elements in set A. If n(A) =p and n(B) ...
Since the order of the pair matters, we need to consider all possible combinations of elements from sets A and B.

For each element in set A, we can choose any of the q elements in set B, giving us q choices for b. Therefore, for one fixed value of a, there are q possible values of b.

Since there are p elements in set A, there are p choices for a. Therefore, the total number of ordered pairs (a, b) is:

p x q = pq
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Community Answer
Let n(A) denotes the number of elements in set A. If n(A) =p and n(B) ...
2pq
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Let n(A) denotes the number of elements in set A. If n(A) =p and n(B) = q, then how many ordered pairs (a, b) are there with a ∈ A and b ∈ B ?a)p2b)p x qc)p + qd)2 pqCorrect answer is option 'B'. Can you explain this answer?
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