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In the following code segment what will be the result of the function,value of x , value of y
{unsigned int x=-1;
int y;
y = ~0;
if(x == y)
printf("same");
else
printf("not same");
}
- a)same, MAXINT, -1
- b)not same, MAXINT, -MAXINT
- c)same , MAXUNIT, -1
- d)same, MAXUNIT, MAXUNIT
- e)not same, MAXINT, MAXUNIT
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In the following code segment what will be the result of the function,...
The code segment is incomplete and missing the ending of the printf statement. However, based on the given code, the following can be inferred:
- The variable x is an unsigned integer initialized to -1, which is equivalent to the maximum value an unsigned integer can hold.
- The variable y is an integer and is uninitialized.
- The variable y is assigned the value of the bitwise complement of 0, which is a sequence of all 1's.
- The if statement compares the values of x and y. Since x is an unsigned integer and y is an integer, they will be compared as if y was cast to an unsigned integer.
- The value of x and y will be the same since they both represent a sequence of all 1's.
- The printf statement is incomplete and will result in a compilation error.
Overall, the code segment sets the value of x and y to all 1's and compares them to demonstrate the difference in behavior between unsigned integers and signed integers when dealing with bitwise operations.
- The variable x is an unsigned integer initialized to -1, which is equivalent to the maximum value an unsigned integer can hold.
- The variable y is an integer and is uninitialized.
- The variable y is assigned the value of the bitwise complement of 0, which is a sequence of all 1's.
- The if statement compares the values of x and y. Since x is an unsigned integer and y is an integer, they will be compared as if y was cast to an unsigned integer.
- The value of x and y will be the same since they both represent a sequence of all 1's.
- The printf statement is incomplete and will result in a compilation error.
Overall, the code segment sets the value of x and y to all 1's and compares them to demonstrate the difference in behavior between unsigned integers and signed integers when dealing with bitwise operations.
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In the following code segment what will be the result of the function,value of x , value of y{unsigned int x=-1;int y;y = ~0;if(x == y)printf("same");elseprintf("not same");}a)same, MAXINT, -1b)not same, MAXINT, -MAXINTc)same , MAXUNIT, -1d)same, MAXUNIT, MAXUNITe)not same, MAXINT, MAXUNITCorrect answer is option 'A'. Can you explain this answer?
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In the following code segment what will be the result of the function,value of x , value of y{unsigned int x=-1;int y;y = ~0;if(x == y)printf("same");elseprintf("not same");}a)same, MAXINT, -1b)not same, MAXINT, -MAXINTc)same , MAXUNIT, -1d)same, MAXUNIT, MAXUNITe)not same, MAXINT, MAXUNITCorrect answer is option 'A'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about In the following code segment what will be the result of the function,value of x , value of y{unsigned int x=-1;int y;y = ~0;if(x == y)printf("same");elseprintf("not same");}a)same, MAXINT, -1b)not same, MAXINT, -MAXINTc)same , MAXUNIT, -1d)same, MAXUNIT, MAXUNITe)not same, MAXINT, MAXUNITCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the following code segment what will be the result of the function,value of x , value of y{unsigned int x=-1;int y;y = ~0;if(x == y)printf("same");elseprintf("not same");}a)same, MAXINT, -1b)not same, MAXINT, -MAXINTc)same , MAXUNIT, -1d)same, MAXUNIT, MAXUNITe)not same, MAXINT, MAXUNITCorrect answer is option 'A'. Can you explain this answer?.
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