How many moles of magnesium phosphate Mg3(PO4)2 will contain 0.25 mole of oxygen atoms?

Question

Answer

Calculation of Moles of Magnesium Phosphate

Given Information:

Step-by-Step Solution:

Determine the number of oxygen atoms in one molecule of magnesium phosphate.
- There are 4 oxygen atoms in one molecule of magnesium phosphate (2 in PO4 and 2 in Mg3).

Calculate the number of molecules of oxygen atoms in 0.25 moles of oxygen atoms.
- Number of atoms in 0.25 moles of oxygen atoms: 0.25 × 6.02 × 10^23 = 1.505 × 10^23 atoms
- Number of molecules of oxygen atoms: 1.505 × 10^23 atoms ÷ 4 atoms/molecule = 3.7625 × 10^22 molecules

Calculate the number of molecules of magnesium phosphate that contain 3.7625 × 10^22 molecules of oxygen atoms.
- Number of molecules of magnesium phosphate: 3.7625 × 10^22 molecules ÷ (2 × 4 molecules of oxygen atoms/molecule) = 9.40625 × 10^21 molecules

Convert the number of molecules of magnesium phosphate to moles.
- Number of moles of magnesium phosphate: 9.40625 × 10^21 molecules × (1 mole/6.02 × 10^23 molecules) = 0.015625 moles

Answer:

0.25 mole of oxygen atoms is equivalent to 0.015625 mole of magnesium phosphate.

Answer

1 mole of Mg3(PO)2 contain 8 mole of oxygen so 1 mole of oxygen contain 1/8 mole of Mg3(PO) 2 so 0.25 mole of oxygen =0.25*1/8=0.03 mole