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In which case is the number of molecules of watermaximum?
- a)18 mL of water
- b)0.18 g of water
- c)0.00224 L of water vapours at 1 atm and273 K
- d)10–3 mol of water
Correct answer is option 'A'. Can you explain this answer?
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In which case is the number of molecules of watermaximum?a)18 mL of wa...
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cause no of mole is directly proportional to no of molecules
moles =weight / mol wt
=18/18=1mole highest in all the answers
cause no of mole is directly proportional to no of molecules
moles =weight / mol wt
=18/18=1mole highest in all the answers
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In which case is the number of molecules of watermaximum?a)18 mL of wa...
Understanding the Number of Molecules of Water
To determine the maximum number of molecules of water in the given options, we need to calculate the number of moles in each case and then use Avogadro's number to find the total number of molecules.
1. Calculating for Each Option
- Option A: 18 mL of Water
- The density of water is approximately 1 g/mL.
- Therefore, 18 mL of water = 18 g.
- Moles of water = mass (g) / molar mass (g/mol) = 18 g / 18 g/mol = 1 mol.
- Number of molecules = 1 mol × 6.022 × 10²³ = 6.022 × 10²³ molecules.
- Option B: 0.18 g of Water
- Moles of water = 0.18 g / 18 g/mol = 0.01 mol.
- Number of molecules = 0.01 mol × 6.022 × 10²³ = 6.022 × 10²¹ molecules.
- Option C: 0.00224 L of Water Vapors at 1 atm and 273 K
- Using the ideal gas law, we know 1 mol of gas occupies 22.4 L at STP.
- Moles = 0.00224 L / 22.4 L/mol = 0.0001 mol.
- Number of molecules = 0.0001 mol × 6.022 × 10²³ = 6.022 × 10²⁰ molecules.
- Option D: 10–3 mol of Water
- Number of molecules = 10–3 mol × 6.022 × 10²³ = 6.022 × 10²⁰ molecules.
2. Conclusion
From the calculations above:
- 18 mL of water yields 6.022 × 10²³ molecules, which is significantly higher than the other options.
- Thus, the option with the maximum number of water molecules is indeed Option A: 18 mL of Water.
To determine the maximum number of molecules of water in the given options, we need to calculate the number of moles in each case and then use Avogadro's number to find the total number of molecules.
1. Calculating for Each Option
- Option A: 18 mL of Water
- The density of water is approximately 1 g/mL.
- Therefore, 18 mL of water = 18 g.
- Moles of water = mass (g) / molar mass (g/mol) = 18 g / 18 g/mol = 1 mol.
- Number of molecules = 1 mol × 6.022 × 10²³ = 6.022 × 10²³ molecules.
- Option B: 0.18 g of Water
- Moles of water = 0.18 g / 18 g/mol = 0.01 mol.
- Number of molecules = 0.01 mol × 6.022 × 10²³ = 6.022 × 10²¹ molecules.
- Option C: 0.00224 L of Water Vapors at 1 atm and 273 K
- Using the ideal gas law, we know 1 mol of gas occupies 22.4 L at STP.
- Moles = 0.00224 L / 22.4 L/mol = 0.0001 mol.
- Number of molecules = 0.0001 mol × 6.022 × 10²³ = 6.022 × 10²⁰ molecules.
- Option D: 10–3 mol of Water
- Number of molecules = 10–3 mol × 6.022 × 10²³ = 6.022 × 10²⁰ molecules.
2. Conclusion
From the calculations above:
- 18 mL of water yields 6.022 × 10²³ molecules, which is significantly higher than the other options.
- Thus, the option with the maximum number of water molecules is indeed Option A: 18 mL of Water.
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In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer?
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In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer?.
In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which case is the number of molecules of watermaximum?a)18 mL of waterb)0.18 g of waterc)0.00224 L of water vapours at 1 atm and273 Kd)10–3 mol of waterCorrect answer is option 'A'. Can you explain this answer?.
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