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A 50 Hz. 4 pole turbo generator rated 200 MVA, 13 kV has an inertia constant of 6 MJ/MVA. If mechanical input is suddenly raised to 100 MW for an electrical load of 80 MW, then its rotor accelerations – (in elec-deg/sec2)
    Correct answer is between '149,151'. Can you explain this answer?
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    A 50 Hz. 4 pole turbo generator rated 200 MVA, 13 kV has an inertia co...
    Given that,
    S = 200 MVA
    H = 6 MJ/MVA
    F = 50 Hz
    Pa = Ps – Pe = 100 – 80 = 20 Mw
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    Most Upvoted Answer
    A 50 Hz. 4 pole turbo generator rated 200 MVA, 13 kV has an inertia co...
    The rotor acceleration of the turbo generator can be calculated using the equation:

    acceleration = (mechanical input - electrical output) / (inertia constant x generator rating)

    where mechanical input is in MW, electrical output is in MW, inertia constant is in MJ/MVA, and generator rating is in MVA.

    Substituting the given values, we get:

    acceleration = (100 - 80) / (6 x 200) = 0.0833 rad/sec^2

    Therefore, the rotor acceleration of the turbo generator is 0.0833 rad/sec^2.
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    A 50 Hz. 4 pole turbo generator rated 200 MVA, 13 kV has an inertia constant of 6 MJ/MVA. If mechanical input is suddenly raised to 100 MW for an electrical load of 80 MW, then its rotor accelerations – (in elec-deg/sec2)Correct answer is between '149,151'. Can you explain this answer?
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