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A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared
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the Electrical Engineering (EE) exam syllabus. Information about A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer?.
Solutions for A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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Here you can find the meaning of A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 2 MVA, 3.3 kV, three-phase generator as the following reactance’s on its own base:+ve sequence reactance, x1= j0.10 p.u.-ve sequence reactance, x2= j0.10 p.u.Zero sequence reactance, x0= j0.05 p.u.Reactance from neutral to ground, xn= j0.05 p.u.The generator supplies a 3-phase, 1.5 MVA balanced passive load through a 3-phase, 2.0 MVA, 3.3 kV/400 V, delta-star transform with leakage reactance of 10%, as shown in the figure. A single-line-to-ground fault takes place at the low voltage side of the transformer. The current flowing from the transformer to the fault is (Assume base MVA is 1.5 MVA)a)5773.5 Ab)12371.8 Ac)14433.8 Ad)17320.5 ACorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.