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Study the following arrangement and answer questions given:
648 483 295 333 261 312
Q. If one is subtracted from all even digits in the numbers, then in how many numbers, a digit appear twice within a number?
  • a)
    None
  • b)
    One
  • c)
    Two
  • d)
    Three
  • e)
    More than three
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
Study the following arrangement and answer questions given:648 483 295...
Numbers become: 537 373 195 333 151 211
So: 373, 333, 151, and 211.
This question is part of UPSC exam. View all LR courses
Most Upvoted Answer
Study the following arrangement and answer questions given:648 483 295...
Arrangement Analysis:

The given arrangement is:
648 483 295 333 261 312

Approach:

- We need to subtract 1 from all even digits in the given numbers.
- Then we need to check in how many numbers, a digit appears twice within a number.

Calculation:

- Subtracting 1 from all even digits in the given numbers, we get:

548 383 195 333 251 311

- Checking for numbers in which a digit appears twice within a number:

- In the number 383, digit 3 appears twice.
- In the number 333, digit 3 appears thrice.
- In the number 251, digit 1 appears twice.

- Hence, there are more than three numbers in which a digit appears twice within a number.

Answer: Option E. More than three.
Community Answer
Study the following arrangement and answer questions given:648 483 295...
Hi all,
The sequence given is,
648, 483, 295, 333, 261, 312

By subtracting 1 in all even digits within the number the sequence becomes

537, 373, 195, 333, 151, 311

Now following are the numbers with same two digits within them
1. 373
2. 333
3. 151
4. 311

Hence more than 3 numbers have repetitive digits in them. OPTION E is the correct answer.
I hope you all understand this explanation .
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