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An organic compound A (c2h3n) on reduction gives B .B on reaction with hno2 gives ethyl alcohol.again B when reacts with chloroform and alcoholic koh gives a compound C having obnoxious smell .identify A,B,C with equation. Plzz mujhe jaldi Bata do koi?
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Identification of Organic Compounds A, B, and C with Equations
Introduction:
In this problem, we are given an organic compound A (C2H3N) which upon reduction gives compound B. Further, compound B reacts with HNO2 to form ethyl alcohol. Finally, compound B reacts with chloroform and alcoholic KOH to produce a compound C with an obnoxious smell.
Identification of Compound A:
The molecular formula of compound A is C2H3N. From this formula, we can deduce that it contains 2 carbon atoms, 3 hydrogen atoms, and 1 nitrogen atom. The presence of nitrogen suggests that compound A is an amine.
Identification of Compound B:
Compound B is obtained by the reduction of compound A. Reduction reactions typically involve the addition of hydrogen atoms or the removal of oxygen atoms. In this case, compound B is formed by adding hydrogen to compound A. Therefore, compound B is an amine, similar to compound A.
Identification of Compound C:
Compound C is formed by the reaction of compound B with chloroform (CHCl3) and alcoholic KOH (potassium hydroxide). This reaction is known as the Carbylamine reaction. The Carbylamine reaction is specific to primary amines, which means compound B must be a primary amine.
The Carbylamine reaction involves the replacement of the amino group (-NH2) of the primary amine with a cyanide group (-CN) from chloroform. The reaction can be represented as follows:
R-NH2 + CHCl3 + KOH -> R-NCO + 3KCl + 3H2O
In this reaction, compound B reacts with chloroform and alcoholic KOH to form compound C, which has an obnoxious smell. Compound C is an isocyanide, also known as carbylamine. The presence of the isocyanide group gives compound C its characteristic odor.
Summary:
- Compound A is an amine with the molecular formula C2H3N.
- Compound B is obtained by the reduction of compound A and is also an amine.
- Compound B reacts with chloroform and alcoholic KOH to form compound C, which is an isocyanide (carbylamine) with an obnoxious smell.
Equations:
1. Reduction of compound A to form compound B:
C2H3N + H2 -> B
2. Reaction of compound B with HNO2 to form ethyl alcohol:
B + HNO2 -> Ethyl alcohol (C2H5OH)
3. Carbylamine reaction of compound B with chloroform and alcoholic KOH to form compound C:
B + CHCl3 + KOH -> C (Isocyanide/Carbylamine) + 3KCl + 3H2O
Introduction:
In this problem, we are given an organic compound A (C2H3N) which upon reduction gives compound B. Further, compound B reacts with HNO2 to form ethyl alcohol. Finally, compound B reacts with chloroform and alcoholic KOH to produce a compound C with an obnoxious smell.
Identification of Compound A:
The molecular formula of compound A is C2H3N. From this formula, we can deduce that it contains 2 carbon atoms, 3 hydrogen atoms, and 1 nitrogen atom. The presence of nitrogen suggests that compound A is an amine.
Identification of Compound B:
Compound B is obtained by the reduction of compound A. Reduction reactions typically involve the addition of hydrogen atoms or the removal of oxygen atoms. In this case, compound B is formed by adding hydrogen to compound A. Therefore, compound B is an amine, similar to compound A.
Identification of Compound C:
Compound C is formed by the reaction of compound B with chloroform (CHCl3) and alcoholic KOH (potassium hydroxide). This reaction is known as the Carbylamine reaction. The Carbylamine reaction is specific to primary amines, which means compound B must be a primary amine.
The Carbylamine reaction involves the replacement of the amino group (-NH2) of the primary amine with a cyanide group (-CN) from chloroform. The reaction can be represented as follows:
R-NH2 + CHCl3 + KOH -> R-NCO + 3KCl + 3H2O
In this reaction, compound B reacts with chloroform and alcoholic KOH to form compound C, which has an obnoxious smell. Compound C is an isocyanide, also known as carbylamine. The presence of the isocyanide group gives compound C its characteristic odor.
Summary:
- Compound A is an amine with the molecular formula C2H3N.
- Compound B is obtained by the reduction of compound A and is also an amine.
- Compound B reacts with chloroform and alcoholic KOH to form compound C, which is an isocyanide (carbylamine) with an obnoxious smell.
Equations:
1. Reduction of compound A to form compound B:
C2H3N + H2 -> B
2. Reaction of compound B with HNO2 to form ethyl alcohol:
B + HNO2 -> Ethyl alcohol (C2H5OH)
3. Carbylamine reaction of compound B with chloroform and alcoholic KOH to form compound C:
B + CHCl3 + KOH -> C (Isocyanide/Carbylamine) + 3KCl + 3H2O
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An organic compound A (c2h3n) on reduction gives B .B on reaction with hno2 gives ethyl alcohol.again B when reacts with chloroform and alcoholic koh gives a compound C having obnoxious smell .identify A,B,C with equation. Plzz mujhe jaldi Bata do koi?
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An organic compound A (c2h3n) on reduction gives B .B on reaction with hno2 gives ethyl alcohol.again B when reacts with chloroform and alcoholic koh gives a compound C having obnoxious smell .identify A,B,C with equation. Plzz mujhe jaldi Bata do koi? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An organic compound A (c2h3n) on reduction gives B .B on reaction with hno2 gives ethyl alcohol.again B when reacts with chloroform and alcoholic koh gives a compound C having obnoxious smell .identify A,B,C with equation. Plzz mujhe jaldi Bata do koi? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound A (c2h3n) on reduction gives B .B on reaction with hno2 gives ethyl alcohol.again B when reacts with chloroform and alcoholic koh gives a compound C having obnoxious smell .identify A,B,C with equation. Plzz mujhe jaldi Bata do koi?.
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