NEET Exam > NEET Questions > A gas at 350 K and 15 bar has molar volume 20...
Start Learning for Free
A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :
- a)Z > 1 and attractive forces are dominant
- b)Z > 1 and repulsive forces are dominant
- c)Z < 1 and attractive forces are dominant
- d)Z < 1 and repulsive forces are dominant
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A gas at 350 K and 15 bar has molar volume 20 percent smaller than tha...
Compressibility factor(Z) 
∵ Vreal < Videal; Hence Z < 1
If Z < 1, attractive forces are dominant among gaseous molecules and liquefaction of gas will be easy.
∵ Vreal < Videal; Hence Z < 1
If Z < 1, attractive forces are dominant among gaseous molecules and liquefaction of gas will be easy.
Most Upvoted Answer
A gas at 350 K and 15 bar has molar volume 20 percent smaller than tha...
The correct option about the gas and its compressibility factor (Z) cannot be determined from the given information alone.
Explanation:
The molar volume of an ideal gas at 350 K and 15 bar can be calculated using the ideal gas law:
PV = nRT
where P = 15 bar, V is the molar volume, n is the number of moles, R is the gas constant, and T = 350 K.
Rearranging, we get:
V = (nRT)/P
If we assume that the gas is ideal, then we can use this equation to find the molar volume of the gas:
Videal = (nRT)/P = (1 mol)(8.314 J/mol-K)(350 K)/(15 bar) = 152.8 cm^3/mol
However, the problem states that the actual molar volume of the gas is 20% smaller than this value. This means that the actual molar volume is:
Vactual = 0.8 Videal = 0.8(152.8 cm^3/mol) = 122.24 cm^3/mol
Now, we can use the definition of compressibility factor (Z) to relate the actual molar volume to the molar volume of an ideal gas at the same conditions:
Z = (PVactual)/(nRT) = (15 bar)(122.24 cm^3/mol)/(1 mol)(8.314 J/mol-K)(350 K)
Z = 0.997
This value of Z is very close to 1, which suggests that the gas behaves almost like an ideal gas under these conditions. However, we cannot determine if the gas is actually ideal or not without more information about its properties or behavior.
Explanation:
The molar volume of an ideal gas at 350 K and 15 bar can be calculated using the ideal gas law:
PV = nRT
where P = 15 bar, V is the molar volume, n is the number of moles, R is the gas constant, and T = 350 K.
Rearranging, we get:
V = (nRT)/P
If we assume that the gas is ideal, then we can use this equation to find the molar volume of the gas:
Videal = (nRT)/P = (1 mol)(8.314 J/mol-K)(350 K)/(15 bar) = 152.8 cm^3/mol
However, the problem states that the actual molar volume of the gas is 20% smaller than this value. This means that the actual molar volume is:
Vactual = 0.8 Videal = 0.8(152.8 cm^3/mol) = 122.24 cm^3/mol
Now, we can use the definition of compressibility factor (Z) to relate the actual molar volume to the molar volume of an ideal gas at the same conditions:
Z = (PVactual)/(nRT) = (15 bar)(122.24 cm^3/mol)/(1 mol)(8.314 J/mol-K)(350 K)
Z = 0.997
This value of Z is very close to 1, which suggests that the gas behaves almost like an ideal gas under these conditions. However, we cannot determine if the gas is actually ideal or not without more information about its properties or behavior.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer?
Question Description
A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer?.
A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :a)Z > 1 and attractive forces are dominantb)Z > 1 and repulsive forces are dominantc)Z < 1 and attractive forces are dominantd)Z < 1 and repulsive forces are dominantCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup