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A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How?
Most Upvoted Answer
A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the samp...
Calculation of the mass of the Na2CO3 sample:
Given:
Number of Na ions (Na+) = 6.02 × 10^23
In order to calculate the mass of the Na2CO3 sample, we need to use the molar mass of Na2CO3 and the Avogadro's number.
1. Molar mass of Na2CO3:
The molar mass of Na2CO3 can be calculated by adding up the atomic masses of each element in the compound.
Na: atomic mass = 22.99 g/mol
C: atomic mass = 12.01 g/mol
O: atomic mass = 16.00 g/mol
Molar mass of Na2CO3 = (2 * atomic mass of Na) + atomic mass of C + (3 * atomic mass of O)
= (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol)
= 45.98 g/mol + 12.01 g/mol + 48.00 g/mol
= 105.99 g/mol
2. Calculation of the mass of the Na2CO3 sample:
Using the equation: mass = (number of particles * molar mass) / Avogadro's number
mass = (6.02 × 10^23 * 105.99 g/mol) / 6.022 × 10^23 mol^-1
= 105.99 g
Therefore, the mass of the Na2CO3 sample is 105.99 g.
Explanation:
The given answer of 53g is incorrect. The correct mass of the Na2CO3 sample is 105.99 g, not 53 g. It is possible that there was an error in the answer key or in the calculation. It is always important to double-check calculations and refer to reliable sources for accurate information.
Given:
Number of Na ions (Na+) = 6.02 × 10^23
In order to calculate the mass of the Na2CO3 sample, we need to use the molar mass of Na2CO3 and the Avogadro's number.
1. Molar mass of Na2CO3:
The molar mass of Na2CO3 can be calculated by adding up the atomic masses of each element in the compound.
Na: atomic mass = 22.99 g/mol
C: atomic mass = 12.01 g/mol
O: atomic mass = 16.00 g/mol
Molar mass of Na2CO3 = (2 * atomic mass of Na) + atomic mass of C + (3 * atomic mass of O)
= (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol)
= 45.98 g/mol + 12.01 g/mol + 48.00 g/mol
= 105.99 g/mol
2. Calculation of the mass of the Na2CO3 sample:
Using the equation: mass = (number of particles * molar mass) / Avogadro's number
mass = (6.02 × 10^23 * 105.99 g/mol) / 6.022 × 10^23 mol^-1
= 105.99 g
Therefore, the mass of the Na2CO3 sample is 105.99 g.
Explanation:
The given answer of 53g is incorrect. The correct mass of the Na2CO3 sample is 105.99 g, not 53 g. It is possible that there was an error in the answer key or in the calculation. It is always important to double-check calculations and refer to reliable sources for accurate information.
Community Answer
A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the samp...
Na2CO3 -> 2Na+ + CO3^-2
106g = 2 mol Na+ =6.02×10^23 ×2
6.02 ×10^23 = 106/2 = 53g
106g = 2 mol Na+ =6.02×10^23 ×2
6.02 ×10^23 = 106/2 = 53g
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A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How?
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A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How?.
A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of Na2CO3 contains 6.02 × 10^23 Na ions.The mass of the sample is .? a.53g b.106g c.165g d.212g The given answer is 53g.How?.
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