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A solar cell has a short circuit current of 10 mA and open circuit voltage of 0.9 V. The maximum power delivered by the solar cell is _________ mV. Given fill factor as 0.8.
Correct answer is between '7,7.3'. Can you explain this answer?
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A solar cell has a short circuit current of 10 mA and open circuit vol...
The maximum power delivered Pm = Vm. Im = f.f × VOC ISC
= 0.8 × 0.9 × 10 mA
= 7.2 mW
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A solar cell has a short circuit current of 10 mA and open circuit vol...
Short circuit current:
The short circuit current (Isc) of a solar cell is the current that flows through the cell when it is connected directly to a short circuit. In this case, the short circuit current is given as 10 mA.
Open circuit voltage:
The open circuit voltage (Voc) of a solar cell is the voltage across the cell when it is not connected to any load or circuit. In this case, the open circuit voltage is given as 0.9 V.
Calculating maximum power:
The maximum power (Pmax) that can be delivered by a solar cell is given by the product of the voltage and current at the maximum power point (MPP). The MPP is the operating point on the current-voltage (I-V) curve of the solar cell where the product of voltage and current is maximum.
To find the MPP, we can plot the I-V curve of the solar cell. The I-V curve is typically a curve with a knee-like shape, where the current increases rapidly at low voltages and then levels off at higher voltages.
Using the fill factor:
The fill factor (FF) of a solar cell is a measure of how well the solar cell performs relative to its theoretical maximum power output. It is defined as the ratio of the maximum power output of the solar cell to the product of its open circuit voltage and short circuit current.
FF = Pmax / (Voc * Isc)
Given that the fill factor is 0.8, we can rearrange the equation to solve for Pmax:
Pmax = FF * Voc * Isc
Substituting the given values:
Pmax = 0.8 * 0.9 V * 10 mA = 7.2 mW
Conclusion:
Therefore, the maximum power delivered by the solar cell is 7.2 mW, which is within the range of 7 to 7.3 mW.
The short circuit current (Isc) of a solar cell is the current that flows through the cell when it is connected directly to a short circuit. In this case, the short circuit current is given as 10 mA.
Open circuit voltage:
The open circuit voltage (Voc) of a solar cell is the voltage across the cell when it is not connected to any load or circuit. In this case, the open circuit voltage is given as 0.9 V.
Calculating maximum power:
The maximum power (Pmax) that can be delivered by a solar cell is given by the product of the voltage and current at the maximum power point (MPP). The MPP is the operating point on the current-voltage (I-V) curve of the solar cell where the product of voltage and current is maximum.
To find the MPP, we can plot the I-V curve of the solar cell. The I-V curve is typically a curve with a knee-like shape, where the current increases rapidly at low voltages and then levels off at higher voltages.
Using the fill factor:
The fill factor (FF) of a solar cell is a measure of how well the solar cell performs relative to its theoretical maximum power output. It is defined as the ratio of the maximum power output of the solar cell to the product of its open circuit voltage and short circuit current.
FF = Pmax / (Voc * Isc)
Given that the fill factor is 0.8, we can rearrange the equation to solve for Pmax:
Pmax = FF * Voc * Isc
Substituting the given values:
Pmax = 0.8 * 0.9 V * 10 mA = 7.2 mW
Conclusion:
Therefore, the maximum power delivered by the solar cell is 7.2 mW, which is within the range of 7 to 7.3 mW.
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A solar cell has a short circuit current of 10 mA and open circuit voltage of 0.9 V. The maximum power delivered by the solar cell is _________ mV. Given fill factor as 0.8.Correct answer is between '7,7.3'. Can you explain this answer?
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