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An ideal solar cell has a short-circuit current of 50 mA and an open circuit voltage of 0.7 V under full illumination. The power delivered to a load of 1 kΩ is ________ mW
Correct answer is between '0.4,0.5'. Can you explain this answer?
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Verified Answer
An ideal solar cell has a short-circuit current of 50 mA and an open c...
Given,
VOC = 0.7 V, ISC = 50 mA
Drawing equivalent circuit
Most Upvoted Answer
An ideal solar cell has a short-circuit current of 50 mA and an open c...
The power delivered to a load can be calculated using the formula:
P = V * I
where P is power, V is voltage, and I is current.
Given:
Short-circuit current (Isc) = 50 mA = 0.05 A
Open circuit voltage (Voc) = 0.7 V
Load resistance (R) = 1 kΩ = 1000 Ω
To calculate the power delivered to the load, we need to find the current passing through the load (Iload) and the voltage across the load (Vload).
To find Iload, we can use Ohm's Law:
Iload = Voc / R
Iload = 0.7 V / 1000 Ω
Iload = 0.0007 A = 0.7 mA
To find Vload, we can use Ohm's Law:
Vload = Isc * R
Vload = 0.05 A * 1000 Ω
Vload = 50 V
Now, we can calculate the power delivered to the load:
P = Vload * Iload
P = 50 V * 0.7 mA
P = 35 mW
Therefore, the power delivered to the load is 35 mW.
P = V * I
where P is power, V is voltage, and I is current.
Given:
Short-circuit current (Isc) = 50 mA = 0.05 A
Open circuit voltage (Voc) = 0.7 V
Load resistance (R) = 1 kΩ = 1000 Ω
To calculate the power delivered to the load, we need to find the current passing through the load (Iload) and the voltage across the load (Vload).
To find Iload, we can use Ohm's Law:
Iload = Voc / R
Iload = 0.7 V / 1000 Ω
Iload = 0.0007 A = 0.7 mA
To find Vload, we can use Ohm's Law:
Vload = Isc * R
Vload = 0.05 A * 1000 Ω
Vload = 50 V
Now, we can calculate the power delivered to the load:
P = Vload * Iload
P = 50 V * 0.7 mA
P = 35 mW
Therefore, the power delivered to the load is 35 mW.
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An ideal solar cell has a short-circuit current of 50 mA and an open circuit voltage of 0.7 V under full illumination. The power delivered to a load of 1 kΩ is ________ mWCorrect answer is between '0.4,0.5'. Can you explain this answer?
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