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The ratio of hole diffusion current to the electron diffusion current in an infinite p-n junction is 4. If conductivity on p-side is 1.4 S/cm and on n-side is 2.8 S/cm, then the ratio of diffusion length Ln and Lp (ie Ln/Lp) is _______.
    Correct answer is between '7.8,8.2'. Can you explain this answer?
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    The ratio of hole diffusion current to the electron diffusion current ...
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    The ratio of hole diffusion current to the electron diffusion current ...
    Given:
    - Ratio of hole diffusion current to electron diffusion current in an infinite p-n junction = 4
    - Conductivity on p-side (σp) = 1.4 S/cm
    - Conductivity on n-side (σn) = 2.8 S/cm
    - We need to find the ratio of diffusion length Ln/Lp

    Solution:

    1. Introduction to p-n junction:
    - A p-n junction is formed when a p-type semiconductor is brought into contact with an n-type semiconductor.
    - The p-type region is dominated by holes (positive charge carriers), while the n-type region is dominated by electrons (negative charge carriers).
    - At the junction, the holes and electrons diffuse across the junction due to the concentration gradient.

    2. Diffusion current in a p-n junction:
    - Diffusion current is the current due to the diffusion of charge carriers across the junction.
    - The hole diffusion current (Jp) is given by Jp = qDp(dp/dx), where q is the charge of a hole, Dp is the hole diffusion coefficient, and dp/dx is the concentration gradient of holes.
    - Similarly, the electron diffusion current (Jn) is given by Jn = qDn(dn/dx), where q is the charge of an electron, Dn is the electron diffusion coefficient, and dn/dx is the concentration gradient of electrons.

    3. Ratio of hole diffusion current to electron diffusion current:
    - The ratio of hole diffusion current to electron diffusion current is given by Jp/Jn = (qDp(dp/dx))/(qDn(dn/dx)).
    - Since q is common to both terms, it cancels out.
    - The ratio becomes Jp/Jn = (Dp(dp/dx))/(Dn(dn/dx)).

    4. Relationship between diffusion length and diffusion coefficient:
    - Diffusion coefficient is related to the diffusion length by D = μkT/q, where D is the diffusion coefficient, μ is the mobility, k is the Boltzmann constant, T is the temperature, and q is the charge.
    - The diffusion length (L) is given by L = sqrt(Dτ), where L is the diffusion length, D is the diffusion coefficient, and τ is the carrier lifetime.

    5. Calculation of Ln/Lp:
    - Let Ln and Lp be the diffusion lengths of electrons and holes, respectively.
    - The ratio of diffusion lengths Ln/Lp can be obtained by taking the square root of the ratio of diffusion coefficients (Dn/Dp).
    - Since the conductivity (σ) is the reciprocal of the diffusion coefficient (σ = 1/D), we can write D = 1/σ.
    - The ratio of diffusion lengths Ln/Lp is given by Ln/Lp = sqrt((Dn/σn)/(Dp/σp)).
    - Substituting the given values, Ln/Lp = sqrt((2.8/1.4)/(1/2.8)) = sqrt((2.8^2)/(1.4^2)) = sqrt(7.84) = 2.8.

    6. Conclusion:
    - The ratio of diffusion length Ln/Lp is 2.8.
    - The correct answer is not between 7.8 and 8.
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    The ratio of hole diffusion current to the electron diffusion current in an infinite p-n junction is 4. If conductivity on p-side is 1.4 S/cm and on n-side is 2.8 S/cm, then the ratio of diffusion length Lnand Lp(ie Ln/Lp) is _______.Correct answer is between '7.8,8.2'. Can you explain this answer?
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    The ratio of hole diffusion current to the electron diffusion current in an infinite p-n junction is 4. If conductivity on p-side is 1.4 S/cm and on n-side is 2.8 S/cm, then the ratio of diffusion length Lnand Lp(ie Ln/Lp) is _______.Correct answer is between '7.8,8.2'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The ratio of hole diffusion current to the electron diffusion current in an infinite p-n junction is 4. If conductivity on p-side is 1.4 S/cm and on n-side is 2.8 S/cm, then the ratio of diffusion length Lnand Lp(ie Ln/Lp) is _______.Correct answer is between '7.8,8.2'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ratio of hole diffusion current to the electron diffusion current in an infinite p-n junction is 4. If conductivity on p-side is 1.4 S/cm and on n-side is 2.8 S/cm, then the ratio of diffusion length Lnand Lp(ie Ln/Lp) is _______.Correct answer is between '7.8,8.2'. Can you explain this answer?.
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