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Hole mobility in Ge at room temperature is 1900 cm2/V-sec. The diffusion coefficient is ________cm2/sec.
(Take kT = 25 mV)
Correct answer is between '47,48'. Can you explain this answer?
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Verified Answer
Hole mobility in Ge at room temperature is 1900 cm2/V-sec. The diffusi...
Using the relation
D = 0.025 × 1900 cm2/sec
= 47.5 cm2/sec
Most Upvoted Answer
Hole mobility in Ge at room temperature is 1900 cm2/V-sec. The diffusi...
Given:
Hole mobility in Ge at room temperature = 1900 cm2/V-sec
kT = 25 mV
To find: Diffusion coefficient
Formula used:
Diffusion coefficient (D) = kTq/μ
where,
k = Boltzmann constant (1.38 x 10^-23 J/K)
T = Temperature in Kelvin
q = Charge of a hole (1.6 x 10^-19 C)
μ = Mobility of a hole
Calculation:
Temperature at room temperature = 25 + 273 = 298 K
Charge of a hole (q) = 1.6 x 10^-19 C
Mobility of a hole (μ) = 1900 cm2/V-sec = 1.9 x 10^4 cm^2/m^2-sec (converting cm2/V-sec to m2/V-sec)
Substituting the values in the formula, we get
D = kTq/μ
D = (1.38 x 10^-23 J/K) x (25 x 10^-3 V) x (1.6 x 10^-19 C) / (1.9 x 10^4 cm^2/m^2-sec)
D = 47.8 cm^2/sec (approx.)
Therefore, the diffusion coefficient in Ge at room temperature is approximately 47.8 cm2/sec.
Hole mobility in Ge at room temperature = 1900 cm2/V-sec
kT = 25 mV
To find: Diffusion coefficient
Formula used:
Diffusion coefficient (D) = kTq/μ
where,
k = Boltzmann constant (1.38 x 10^-23 J/K)
T = Temperature in Kelvin
q = Charge of a hole (1.6 x 10^-19 C)
μ = Mobility of a hole
Calculation:
Temperature at room temperature = 25 + 273 = 298 K
Charge of a hole (q) = 1.6 x 10^-19 C
Mobility of a hole (μ) = 1900 cm2/V-sec = 1.9 x 10^4 cm^2/m^2-sec (converting cm2/V-sec to m2/V-sec)
Substituting the values in the formula, we get
D = kTq/μ
D = (1.38 x 10^-23 J/K) x (25 x 10^-3 V) x (1.6 x 10^-19 C) / (1.9 x 10^4 cm^2/m^2-sec)
D = 47.8 cm^2/sec (approx.)
Therefore, the diffusion coefficient in Ge at room temperature is approximately 47.8 cm2/sec.
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Community Answer
Hole mobility in Ge at room temperature is 1900 cm2/V-sec. The diffusi...
Here it's not KT, it's V(t) or thermal voltage, that is 25 mV at 300 k.
And according to Einstein Relationship (D/mobility)=thermal voltage,
answer is 47.5
And according to Einstein Relationship (D/mobility)=thermal voltage,
answer is 47.5
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Hole mobility in Ge at room temperature is 1900 cm2/V-sec. The diffusion coefficient is ________cm2/sec.(Take kT = 25 mV)Correct answer is between '47,48'. Can you explain this answer?
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