S= ut + 1/2 at2
as boby is at rest so intial velocity will become zero
s= 1/2 × a× 8× 8
150 = 32a
a= 150/32
a= 4.6m/s2

Acceleration Calculation:

To find the acceleration of the body, we can use the equation of motion:

\[s = ut + \frac{1}{2}at^2\]

where s is the distance covered, u is the initial velocity, t is the time taken, and a is the acceleration.

Given that the body starts from rest, the initial velocity (u) is 0.

Distance Covered in the 8th Second:

The body covers a distance of 150m during the 8th second of its motion.

Using the equation of motion, we can substitute the values:

\[150 = 0 + \frac{1}{2}a(8^2)\]

Simplifying the equation:

\[150 = 32a\]

Solving for a:

\[a = \frac{150}{32} = 4.6875 \, m/s^2\]

Therefore, the acceleration of the body is \(4.6875 \, m/s^2\).

Explanation:

The given problem can be solved by using the equation of motion. By substituting the appropriate values into the equation, we can find the acceleration of the body.

The equation of motion, \(s = ut + \frac{1}{2}at^2\), relates the distance covered (s), initial velocity (u), time taken (t), and acceleration (a).

In this problem, the body starts from rest, so the initial velocity (u) is 0. Therefore, the equation simplifies to \(s = \frac{1}{2}at^2\).

We are given that the body covers a distance of 150m during the 8th second of its motion. Substituting the values, we get \(150 = 0 + \frac{1}{2}a(8^2)\).

Simplifying the equation gives us \(150 = 32a\). Solving for a, we find \(a = \frac{150}{32} = 4.6875 \, m/s^2\).

Hence, the acceleration of the body is \(4.6875 \, m/s^2\).