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A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :
  • a)
    C2A3
  • b)
    C3A2
  • c)
    C3A4
  • d)
    C4A3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A compound is formed by cation C and anion A. The anions form hexagona...
Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)

= 18/4
= 9/2
So formula of compound will be 

C9A12 ⇒ C3A4
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A compound is formed by cation C and anion A. The anions form hexagona...
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Community Answer
A compound is formed by cation C and anion A. The anions form hexagona...
Explanation:


To determine the formula of the compound, we need to analyze the arrangement of the cations and anions in the crystal lattice.

1. Given Information:

- Anions form a hexagonal close-packed (hcp) lattice.
- Cations occupy 75% of octahedral voids.

2. Hexagonal Close-Packed (HCP) Lattice:

In a hcp lattice, the anions are arranged in a close-packed manner with a hexagonal arrangement in one plane and the third layer directly above the first layer. Each anion is surrounded by six neighboring anions in a hexagonal arrangement.

3. Octahedral Voids:

Octahedral voids are the spaces between the anions in a hcp lattice. These voids are located above and below each hexagonal close-packed layer, forming a repeating pattern.

4. Cations in Octahedral Voids:

According to the given information, the cations occupy 75% of the octahedral voids. This means that for every four octahedral voids, three are occupied by cations.

5. Determining the Formula:

Based on the arrangement of cations and anions, we can determine the formula of the compound.

- Each cation occupies 75% of the octahedral voids, so the ratio of cations to octahedral voids is 3:4.
- Each octahedral void is surrounded by six anions.
- In the formula, the ratio of cations to anions should be such that the charges balance out.

Considering the information above, the formula of the compound is C3A4. This means that there are three cations (C) for every four anions (A), ensuring charge neutrality in the compound.

Therefore, the correct answer is option 'C' (C3A4).
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A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :a)C2A3b)C3A2c)C3A4d)C4A3Correct answer is option 'C'. Can you explain this answer?
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