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 At threshold Voltage, the surface potential is:
  • a)
    – Fermi potential
  • b)
    Fermi potential
  • c)
    2 Fermi potential
  • d)
    -2 Fermi potential
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
At threshold Voltage, the surface potential is:a)– Fermi potenti...
When surface potential reaches –fermi potential, the surface inversion occurs. The gate voltage which brings these changes is known as threshold voltage.
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At threshold Voltage, the surface potential is:a)– Fermi potenti...
Surface Potential at Threshold Voltage
Understanding the concept of surface potential at threshold voltage is crucial in the field of electrical engineering. Let's break down this concept into key points for better comprehension.

Threshold Voltage:
- Threshold voltage is the minimum voltage required to create a conducting channel between the source and drain terminals in a MOSFET.
- It is the point at which the device transitions from the off state to the on state.

Surface Potential:
- Surface potential is the electrostatic potential at the interface between the gate oxide and the semiconductor surface in a MOSFET.
- It plays a significant role in determining the behavior of the device.

Relation to Fermi Potential:
- At threshold voltage, the surface potential is equal to the Fermi potential.
- The Fermi potential represents the energy level at which the probability of finding an electron is 50%.
- Therefore, at threshold voltage, the surface potential is equal to the Fermi potential.

Correct Answer:
- The correct answer to the given question is option 'A' which states that at threshold voltage, the surface potential is equal to - Fermi potential.
By understanding the relationship between surface potential and threshold voltage, one can gain insights into the functioning of MOSFET devices and their applications in various electronic circuits.
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At threshold Voltage, the surface potential is:a)– Fermi potentialb)Fermi potentialc)2 Fermi potentiald)-2 Fermi potentialCorrect answer is option 'A'. Can you explain this answer?
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