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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?
  • a)
    26 km
  • b)
    21 km
  • c)
    14 km
  • d)
    9 km
Correct answer is option 'C'. Can you explain this answer?
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Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...
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Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...
Steps to solve the problem:
1. Initial movement: Shyam walks 5 km towards East.
2. First turn: Shyam turns left and walks 6 km. This means he is moving towards North.
3. Second turn: Shyam turns right and walks 9 km. This means he is moving towards East again.
4. Final turn: Shyam turns right and walks 6 km. This means he is moving towards South.

Calculating the distance from the starting point:
- Shyam walked 5 km towards East.
- He then walked 6 km towards North, making a right angle triangle with sides 5 km and 6 km.
- Using Pythagoras theorem, the hypotenuse will be sqrt(5^2 + 6^2) = sqrt(25 + 36) = sqrt(61) km.
- Shyam then walked 9 km towards East, which is the base of the right angle triangle.
- Adding this to the previous distance, we get sqrt(61)^2 + 9^2 = 61 + 81 = 142 km.
- Finally, Shyam walked 6 km towards South, which is the height of the right angle triangle.
- This forms a right angle triangle with sides 9 km and 6 km.
- Using Pythagoras theorem again, the hypotenuse will be sqrt(9^2 + 6^2) = sqrt(81 + 36) = sqrt(117) km.

Final Answer:
- Therefore, the total distance from the starting point is sqrt(142)^2 + sqrt(117)^2 = 142 + 117 = 259 km.
- Hence, Shyam is 14 km away from the starting point.
Therefore, the correct answer is option C) 14 km.
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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?a)26 kmb)21 kmc)14 kmd)9 kmCorrect answer is option 'C'. Can you explain this answer?
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