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If the derivative of y= 8√sin x is dy/ds =kcosx/√sin x what is the value of numerical constant k?
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If the derivative of y= 8√sin x is dy/ds =kcosx/√sin x what is the val...
Given:

y= 8√sin x

dy/ds = kcosx/√sin x


To Find:

The value of numerical constant k


Solution:

We know that,

dy/dx = 4cos x/√sin x


Let's assume u = sin x

Therefore, du/dx = cos x


Now we can use the chain rule of differentiation,

dy/dx = dy/du * du/dx


Substituting the values,

4cos x/√sin x = dy/du * cos x


Simplifying,

dy/du = 4/√u


Substituting the value of u = sin x,

dy/ds = 4/√sin x


Comparing the given derivative and the above calculated derivative,

k = 4


Answer:

The value of the numerical constant k is 4.
Community Answer
If the derivative of y= 8√sin x is dy/ds =kcosx/√sin x what is the val...
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