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When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C, is [2011]
  • a)
    273 cal/K
  • b)
    8 × 104 cal/K
  • c)
    80 cal/K
  • d)
    293 cal/K
Correct answer is option 'D'. Can you explain this answer?
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When 1 kg of ice at 0°C melts to water at 0°C, the resulting c...
Change in entropy is given by
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When 1 kg of ice at 0°C melts to water at 0°C, the resulting c...
°C is melted, it requires 334 kJ of energy. This is known as the heat of fusion of water. The energy is used to break the intermolecular bonds between the water molecules and convert the ice into liquid water at 0°C. Once all the ice has melted, the liquid water will then absorb additional heat energy to raise its temperature. This is known as the specific heat capacity of water, which is 4.18 J/g°C. So, if the liquid water is heated from 0°C to 100°C, it will require 4.18 kJ of energy per kg per degree Celsius.
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When 1 kg of ice at 0°C melts to water at 0°C, the resulting c...
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When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C, is [2011]a)273 cal/Kb)8 × 104 cal/Kc)80 cal/Kd)293 cal/KCorrect answer is option 'D'. Can you explain this answer?
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When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C, is [2011]a)273 cal/Kb)8 × 104 cal/Kc)80 cal/Kd)293 cal/KCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C, is [2011]a)273 cal/Kb)8 × 104 cal/Kc)80 cal/Kd)293 cal/KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C, is [2011]a)273 cal/Kb)8 × 104 cal/Kc)80 cal/Kd)293 cal/KCorrect answer is option 'D'. Can you explain this answer?.
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