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A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
- a)4 Hz
- b)3 Hz [2005]
- c)2 Hz
- d)1 Hz
Correct answer is option 'D'. Can you explain this answer?
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A particle executing simple harmonic motion of amplitude 5 cm has maxi...
Given data:
Amplitude (A) = 5 cm
Maximum speed = 31.4 cm/s
Calculating frequency:
The maximum speed of a particle in simple harmonic motion occurs at the equilibrium position. At this point, the kinetic energy is maximum and potential energy is minimum.
The maximum speed (Vmax) of a particle in simple harmonic motion is given by the formula:
Vmax = Aω
Where ω is the angular frequency of the particle.
Given that Vmax = 31.4 cm/s and A = 5 cm, we can calculate ω as follows:
31.4 = 5ω
ω = 31.4/5
ω = 6.28 rad/s
The frequency (f) of the particle is related to the angular frequency by the formula:
f = ω/2π
Substitute the value of ω into the formula:
f = 6.28/(2π)
f ≈ 1 Hz
Therefore, the correct answer is option 'd) 1 Hz'.
Amplitude (A) = 5 cm
Maximum speed = 31.4 cm/s
Calculating frequency:
The maximum speed of a particle in simple harmonic motion occurs at the equilibrium position. At this point, the kinetic energy is maximum and potential energy is minimum.
The maximum speed (Vmax) of a particle in simple harmonic motion is given by the formula:
Vmax = Aω
Where ω is the angular frequency of the particle.
Given that Vmax = 31.4 cm/s and A = 5 cm, we can calculate ω as follows:
31.4 = 5ω
ω = 31.4/5
ω = 6.28 rad/s
The frequency (f) of the particle is related to the angular frequency by the formula:
f = ω/2π
Substitute the value of ω into the formula:
f = 6.28/(2π)
f ≈ 1 Hz
Therefore, the correct answer is option 'd) 1 Hz'.
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A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer?.
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation isa)4 Hzb)3 Hz [2005]c)2 Hzd)1 HzCorrect answer is option 'D'. Can you explain this answer?.
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