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The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]
- a)K0/2 and K0
- b)K0 and 2K0
- c)K0 and K0
- d)0 and 2K0.
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The particle executing simple harmonic motion has a kinetic energy K0 ...
Given, Kinetic energy=K0cos2ωt
Maximum kinetic energy=K (as ωt=0 and cos ωt=1
Since total energy remains conserved in SHM , hence when potential energy is maximum,Kinetic energy=0 i.e. E is also equal to Umax i.e. U max(maximum potential energy) = E(Total energy) = K0
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The particle executing simple harmonic motion has a kinetic energy K0 ...
Explanation:
Given:
The kinetic energy of the particle executing simple harmonic motion is K0 cos^2(ωt).
Key Points:
- The potential energy of the particle in simple harmonic motion is given by U = U0 sin^2(ωt), where U0 is the amplitude of the potential energy.
- The total energy of the particle is the sum of kinetic and potential energy, i.e., E = K + U.
Analysis:
- The maximum value of cos^2(ωt) is 1. Therefore, the maximum value of kinetic energy is K0.
- The maximum value of sin^2(ωt) is 1. Therefore, the maximum value of potential energy is U0.
- The maximum value of total energy E will be K0 + U0.
Conclusion:
- The maximum value of potential energy is K0 and the maximum value of total energy is also K0.
- Therefore, the correct answer is option C: K0 and K0.
Given:
The kinetic energy of the particle executing simple harmonic motion is K0 cos^2(ωt).
Key Points:
- The potential energy of the particle in simple harmonic motion is given by U = U0 sin^2(ωt), where U0 is the amplitude of the potential energy.
- The total energy of the particle is the sum of kinetic and potential energy, i.e., E = K + U.
Analysis:
- The maximum value of cos^2(ωt) is 1. Therefore, the maximum value of kinetic energy is K0.
- The maximum value of sin^2(ωt) is 1. Therefore, the maximum value of potential energy is U0.
- The maximum value of total energy E will be K0 + U0.
Conclusion:
- The maximum value of potential energy is K0 and the maximum value of total energy is also K0.
- Therefore, the correct answer is option C: K0 and K0.
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The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer?.
The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The particle executing simple harmonic motion has a kinetic energy K0 cos2ωt . The maximum values of the potential energy and the total energy are respectively [2007]a)K0/2 and K0b)K0 and 2K0c)K0 and K0d)0 and 2K0.Correct answer is option 'C'. Can you explain this answer?.
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