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79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7?
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79. A population is in Hardy-Weinberg equilibrium for a gene with only...
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79. A population is in Hardy-Weinberg equilibrium for a gene with only...
Understanding Hardy-Weinberg Equilibrium
The Hardy-Weinberg principle states that allele and genotype frequencies in a population will remain constant from generation to generation in the absence of evolutionary influences. For a gene with two alleles, 'A' and 'a', the allele frequencies can be denoted as follows:
- Frequency of allele A (p) = 0.7
- Frequency of allele a (q) = 1 - p = 1 - 0.7 = 0.3
Calculating Genotype Frequencies
To determine the expected genotype frequencies, we use the formula:
- Frequency of genotype AA = p²
- Frequency of genotype Aa = 2pq
- Frequency of genotype aa = q²
Now, let’s calculate each frequency:
- Frequency of genotype AA = (0.7)² = 0.49
- Frequency of genotype Aa = 2(0.7)(0.3) = 0.42
- Frequency of genotype aa = (0.3)² = 0.09
Finding the Frequency of Genotype 'aa'
Given that the genotype frequency of 'a' (which refers to 'aa') needs to be established:
- From our calculations, the frequency of genotype aa is q² = 0.09.
Conclusion
Among the options provided:
- (a) 0.21
- (b) 0.42
- (c) 0.36
- (d) 0.7
The correct answer for the frequency of genotype 'aa' is none of the options listed. The calculated frequency of genotype 'aa' is 0.09, which indicates that there might be an error in the provided options.
In summary, the population maintains its genetic structure in Hardy-Weinberg equilibrium, allowing us to derive allele and genotype frequencies accurately.
The Hardy-Weinberg principle states that allele and genotype frequencies in a population will remain constant from generation to generation in the absence of evolutionary influences. For a gene with two alleles, 'A' and 'a', the allele frequencies can be denoted as follows:
- Frequency of allele A (p) = 0.7
- Frequency of allele a (q) = 1 - p = 1 - 0.7 = 0.3
Calculating Genotype Frequencies
To determine the expected genotype frequencies, we use the formula:
- Frequency of genotype AA = p²
- Frequency of genotype Aa = 2pq
- Frequency of genotype aa = q²
Now, let’s calculate each frequency:
- Frequency of genotype AA = (0.7)² = 0.49
- Frequency of genotype Aa = 2(0.7)(0.3) = 0.42
- Frequency of genotype aa = (0.3)² = 0.09
Finding the Frequency of Genotype 'aa'
Given that the genotype frequency of 'a' (which refers to 'aa') needs to be established:
- From our calculations, the frequency of genotype aa is q² = 0.09.
Conclusion
Among the options provided:
- (a) 0.21
- (b) 0.42
- (c) 0.36
- (d) 0.7
The correct answer for the frequency of genotype 'aa' is none of the options listed. The calculated frequency of genotype 'aa' is 0.09, which indicates that there might be an error in the provided options.
In summary, the population maintains its genetic structure in Hardy-Weinberg equilibrium, allowing us to derive allele and genotype frequencies accurately.
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79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7?
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79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7?.
79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7?.
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79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7?, a detailed solution for 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? has been provided alongside types of 79. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele 'A' is 0.7, genotype frequency of 'a' is (a) 0.21 (c) 0.36 (b) 0.42 (d) 0.7? theory, EduRev gives you an
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