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The probability that a leap year will have 53 Fridays or 53 Saturdays is
- a)1/7
- b)2/7
- c)3/7
- d)0
Correct answer is option 'C'. Can you explain this answer?
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The probability that a leap year will have 53 Fridays or 53 Saturdays ...
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The probability that a leap year will have 53 Fridays or 53 Saturdays ...
Solution:
To have 53 Fridays and 53 Saturdays in a year, the year must satisfy the following conditions:
- 1st January should be a Friday.
- There should be no leap year in that particular year.
Now,
- A non-leap year can have either 365 or 366 days.
- If 1st January is a Friday, then 31st December will be a Friday too.
- In between, there are 52 weeks and 1 day.
- Therefore, any non-leap year starting on a Friday will have 53 Fridays and 53 Saturdays only if the following conditions are met:
- The year has 365 days.
- The 1st of January is a Friday.
Now, we need to find the probability of a non-leap year starting on a Friday having 365 days and 1st January being a Friday.
- The probability of a non-leap year having 365 days is 365/365 = 1.
- The probability of 1st January being a Friday is 1/7.
Therefore, the probability of a non-leap year starting on a Friday having 365 days and 1st January being a Friday is:
P = 1 × 1/7 = 1/7
Hence, the correct option is (c) 0.
To have 53 Fridays and 53 Saturdays in a year, the year must satisfy the following conditions:
- 1st January should be a Friday.
- There should be no leap year in that particular year.
Now,
- A non-leap year can have either 365 or 366 days.
- If 1st January is a Friday, then 31st December will be a Friday too.
- In between, there are 52 weeks and 1 day.
- Therefore, any non-leap year starting on a Friday will have 53 Fridays and 53 Saturdays only if the following conditions are met:
- The year has 365 days.
- The 1st of January is a Friday.
Now, we need to find the probability of a non-leap year starting on a Friday having 365 days and 1st January being a Friday.
- The probability of a non-leap year having 365 days is 365/365 = 1.
- The probability of 1st January being a Friday is 1/7.
Therefore, the probability of a non-leap year starting on a Friday having 365 days and 1st January being a Friday is:
P = 1 × 1/7 = 1/7
Hence, the correct option is (c) 0.
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The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer?
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The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer?.
The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability that a leap year will have 53 Fridays or 53 Saturdays isa)1/7b)2/7c)3/7d)0Correct answer is option 'C'. Can you explain this answer?.
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