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The probability of a leap year selected at random contain 53 Sunday is: (a)53/ 366(b)1/7(c)2/7(d) 53/365?
Most Upvoted Answer
The probability of a leap year selected at random contain 53 Sunday is...
No of weeks in leap year = 52weeks + 2 days
these 2 days can be any day of week
therefore P(A) = 2/7
Community Answer
The probability of a leap year selected at random contain 53 Sunday is...
Probability of a Leap Year containing 53 Sundays

Introduction:
A leap year is a year that is evenly divisible by 4, except for years that are divisible by 100. However, years that are divisible by 400 are still considered leap years. In a leap year, February has 29 days instead of the usual 28 days. To find the probability of a leap year containing 53 Sundays, we need to consider the total number of leap years and the number of leap years that have 53 Sundays.

Step 1: Total Number of Leap Years:
To find the total number of leap years, we need to count the number of years that are divisible by 4, excluding the years that are divisible by 100 but not by 400. We can calculate this by considering the range of years from 1 to 400 (inclusive), as this covers all possible cases.

Step 2: Counting Leap Years with 53 Sundays:
To count the number of leap years that contain 53 Sundays, we need to determine the number of Sundays in each month of a leap year. In a regular year, February has 28 days, which means it has 4 weeks and an additional 0 days. However, in a leap year, February has 29 days, which means it has 4 weeks and an additional 1 day.

Step 3: Calculation of Probability:
To calculate the probability, we divide the number of leap years with 53 Sundays by the total number of leap years.

Answer:
The probability of a leap year selected at random containing 53 Sundays is 53/366.
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The probability of a leap year selected at random contain 53 Sunday is: (a)53/ 366(b)1/7(c)2/7(d) 53/365?
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