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Two discs are rotating about their axes, normal to the discs and passing through the centres of the discs. Disc D1 has 2 kg mass and 0.2 m radius and initial angular velocity of  50 rad s–1. Disc D2 has 4kg mass, 0.1 m radius and initial angular velocity of 200 rad s–1. The two discs are brought in contact face to face, with their axes of rotation coincident. The final angular velocity (in rad s–1) of the system is [NEET Kar. 2013]
  • a)
    40
  • b)
    60
  • c)
    100
  • d)
    120
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two discs are rotating about their axes, normal to the discs and passi...
Given: m1 = 2 kg m2 = 4 kg
r1 = 0.2 m r2 = 0.1 m
w1 = 50 rad s–1 w2 = 200 rad s–1
As,   I1W1 = I2W2 = Constant
By putting the value of m1, m2, r1, r2 and solving we get = 100 rad s–1
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Understanding the Problem
When two discs are brought into contact, they may exchange angular momentum. The principle of conservation of angular momentum states that the total angular momentum before the contact must equal the total angular momentum after contact, assuming no external torques are acting on the system.
Calculating Initial Angular Momentum
- Disc D1:
- Mass (m1) = 2 kg
- Radius (r1) = 0.2 m
- Angular velocity (ω1) = 50 rad/s
- Moment of inertia (I1) = 0.5 * m1 * r1^2 = 0.5 * 2 * (0.2^2) = 0.04 kg m²
- Angular momentum (L1) = I1 * ω1 = 0.04 * 50 = 2 kg m²/s
- Disc D2:
- Mass (m2) = 4 kg
- Radius (r2) = 0.1 m
- Angular velocity (ω2) = 200 rad/s
- Moment of inertia (I2) = 0.5 * m2 * r2^2 = 0.5 * 4 * (0.1^2) = 0.02 kg m²
- Angular momentum (L2) = I2 * ω2 = 0.02 * 200 = 4 kg m²/s
Total Initial Angular Momentum
- Total angular momentum before contact (L_total_initial) = L1 + L2 = 2 + 4 = 6 kg m²/s
Final Angular Velocity Calculation
After the discs come into contact, they rotate together with a common final angular velocity (ω_f). The total moment of inertia (I_total) after contact is:
- I_total = I1 + I2 = 0.04 + 0.02 = 0.06 kg m²
Using conservation of angular momentum:
- L_total_initial = I_total * ω_f
- 6 = 0.06 * ω_f
Solving for ω_f:
- ω_f = 6 / 0.06 = 100 rad/s
Conclusion
Thus, the final angular velocity of the system after the two discs come into contact is 100 rad/s, which corresponds to option 'C'.
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Two discs are rotating about their axes, normal to the discs and passing through the centres of the discs. Disc D1 has 2 kg mass and 0.2 m radius and initial angular velocity of 50 rad s–1. Disc D2 has 4kg mass, 0.1 m radius and initial angular velocity of 200 rad s–1. The two discs are brought in contact face to face, with their axes of rotation coincident. The final angular velocity (in rad s–1) of the system is [NEET Kar. 2013]a)40b)60c)100d)120Correct answer is option 'C'. Can you explain this answer?
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