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If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in aproximately [2007]
- a)45 minutes
- b)60 minutes
- c)40 minutes
- d)50 minutes (log 4 = 0.60, log 5 = 0.69)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If 60% of a first order reaction was completed in 60 minutes, 50% of t...
For a first order reaction
when t = 60 and x = 60%
Now,
= 45.31 min.Most Upvoted Answer
If 60% of a first order reaction was completed in 60 minutes, 50% of t...
Given:
- First-order reaction
- 60% of the reaction completed in 60 minutes
To find:
- The time required for 50% of the same reaction to be completed
Explanation:
A first-order reaction follows the rate law equation: Rate = k[A], where [A] represents the concentration of the reactant and k is the rate constant.
Using the formula:
The integrated form of the first-order rate law equation is given by the equation: ln[A]t = -kt + ln[A]0, where [A]t is the concentration of the reactant at time t and [A]0 is the initial concentration.
Given:
- 60% of the reaction completed in 60 minutes
- We can assume the initial concentration ([A]0) to be 100% or 1
Calculating:
Using the given information, we know that when 60% of the reaction is completed, the concentration of the reactant is reduced to 40% or 0.4.
So, plugging in the values into the integrated form of the rate law equation, we get:
ln(0.4) = -k * 60 + ln(1)
Simplifying the equation:
-0.916 = -60k
Solving for k:
k = 0.01527 min^-1
Using the formula:
Now, we need to find the time required for 50% of the reaction to be completed. Let's assume this time as t.
Using the integrated form of the rate law equation again, we get:
ln(0.5) = -0.01527 * t + ln(1)
Simplifying the equation:
-0.6931 = -0.01527 * t
Solving for t:
t = 45.37 minutes
Conclusion:
Therefore, approximately 50% of the same reaction would be completed in approximately 45 minutes. The correct answer is option A.
- First-order reaction
- 60% of the reaction completed in 60 minutes
To find:
- The time required for 50% of the same reaction to be completed
Explanation:
A first-order reaction follows the rate law equation: Rate = k[A], where [A] represents the concentration of the reactant and k is the rate constant.
Using the formula:
The integrated form of the first-order rate law equation is given by the equation: ln[A]t = -kt + ln[A]0, where [A]t is the concentration of the reactant at time t and [A]0 is the initial concentration.
Given:
- 60% of the reaction completed in 60 minutes
- We can assume the initial concentration ([A]0) to be 100% or 1
Calculating:
Using the given information, we know that when 60% of the reaction is completed, the concentration of the reactant is reduced to 40% or 0.4.
So, plugging in the values into the integrated form of the rate law equation, we get:
ln(0.4) = -k * 60 + ln(1)
Simplifying the equation:
-0.916 = -60k
Solving for k:
k = 0.01527 min^-1
Using the formula:
Now, we need to find the time required for 50% of the reaction to be completed. Let's assume this time as t.
Using the integrated form of the rate law equation again, we get:
ln(0.5) = -0.01527 * t + ln(1)
Simplifying the equation:
-0.6931 = -0.01527 * t
Solving for t:
t = 45.37 minutes
Conclusion:
Therefore, approximately 50% of the same reaction would be completed in approximately 45 minutes. The correct answer is option A.
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If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in aproximately [2007]a)45 minutesb)60 minutesc)40 minutesd)50 minutes (log 4 = 0.60, log 5 = 0.69)Correct answer is option 'A'. Can you explain this answer?
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If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in aproximately [2007]a)45 minutesb)60 minutesc)40 minutesd)50 minutes (log 4 = 0.60, log 5 = 0.69)Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in aproximately [2007]a)45 minutesb)60 minutesc)40 minutesd)50 minutes (log 4 = 0.60, log 5 = 0.69)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in aproximately [2007]a)45 minutesb)60 minutesc)40 minutesd)50 minutes (log 4 = 0.60, log 5 = 0.69)Correct answer is option 'A'. Can you explain this answer?.
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