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A stretched string resonates with tuning fork frequency 512 Hz when length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be [1993]
  • a)
    0.25 m
  • b)
    0.5 m
  • c)
    1 m
  • d)
    2 m
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A stretched string resonates with tuning fork frequency 512 Hz when le...
When f is halved, the length
is doubled.
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A stretched string resonates with tuning fork frequency 512 Hz when le...
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A stretched string resonates with tuning fork frequency 512 Hz when length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be [1993]a)0.25 mb)0.5 mc)1 md)2 mCorrect answer is option 'D'. Can you explain this answer?
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A stretched string resonates with tuning fork frequency 512 Hz when length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be [1993]a)0.25 mb)0.5 mc)1 md)2 mCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stretched string resonates with tuning fork frequency 512 Hz when length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be [1993]a)0.25 mb)0.5 mc)1 md)2 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stretched string resonates with tuning fork frequency 512 Hz when length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be [1993]a)0.25 mb)0.5 mc)1 md)2 mCorrect answer is option 'D'. Can you explain this answer?.
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