**Number of Potassium Atoms in 1 Mole of M/5 KMnO4**

To determine the number of potassium atoms required to produce 1 mole of M/5 KMnO4, we need to understand the chemical formula and stoichiometry of the compound.

**Chemical Formula of M/5 KMnO4:**
The chemical formula for potassium permanganate is KMnO4. In the given problem, it is specified as M/5 KMnO4, which means the concentration of KMnO4 is one-fifth (1/5) of the molar concentration of M.

**Stoichiometry of KMnO4:**
The chemical formula KMnO4 tells us that one molecule of potassium permanganate consists of one potassium atom (K), one manganese atom (Mn), and four oxygen atoms (O). Therefore, the ratio of potassium atoms to KMnO4 molecules is 1:1.

**Avogadro's Number:**
Avogadro's number (6.022 × 10^23) represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance.

**Calculating the Number of Potassium Atoms:**
To determine the number of potassium atoms in 1 mole of M/5 KMnO4, we need to consider the molar concentration of the solution.

1 mole of any substance contains Avogadro's number of particles, so 1 mole of M/5 KMnO4 will contain 6.022 × 10^23 KMnO4 molecules.

Since the ratio of potassium atoms to KMnO4 molecules is 1:1, the number of potassium atoms will be the same as the number of KMnO4 molecules.

Therefore, in 1 mole of M/5 KMnO4, there will be 6.022 × 10^23 potassium atoms.

**Conclusion:**
The number of potassium atoms required to produce 1 mole of M/5 KMnO4 is 6.022 × 10^23.

According to mole concept.... Number of atom=moles×avogadro number...so,no.of atom= M/5×6.023×10^23...=1.204×10^23..i hope that helps you....