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An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, its efficiency is doubled. Temperature of the source is
- a)37°C
- b)62°C [2007]
- c)99°C
- d)124°C
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
An engine has an efficiency of 1/6. When the temperature of sink is re...
°F, its efficiency becomes 1/4. Find the initial and final temperatures of the sink.
We can use the formula for the efficiency of a heat engine:
efficiency = 1 - (temperature of sink / temperature of source)
Let's call the initial temperature of the source Ts and the initial temperature of the sink T0. We can set up two equations based on the given information:
1/6 = 1 - (T0 / Ts)
1/4 = 1 - ((T0 - 62) / Ts)
We can solve this system of equations for Ts and T0. One way to do this is to solve for one variable in terms of the other, and then substitute into one of the equations to solve for the remaining variable. Here's one possible method:
1/6 = 1 - (T0 / Ts)
T0 / Ts = 5/6
T0 = (5/6)Ts
1/4 = 1 - ((T0 - 62) / Ts)
(T0 - 62) / Ts = 3/4
T0 - 62 = (3/4)Ts
Substituting T0 = (5/6)Ts into the second equation:
(5/6)Ts - 62 = (3/4)Ts
(1/12)Ts = 62
Ts = 744
Substituting Ts = 744 into T0 = (5/6)Ts:
T0 = (5/6)(744) = 620
Therefore, the initial temperature of the source was 744°F and the initial temperature of the sink was 620°F. When the temperature of the sink was reduced by 62°F, its final temperature was 558°F.
We can use the formula for the efficiency of a heat engine:
efficiency = 1 - (temperature of sink / temperature of source)
Let's call the initial temperature of the source Ts and the initial temperature of the sink T0. We can set up two equations based on the given information:
1/6 = 1 - (T0 / Ts)
1/4 = 1 - ((T0 - 62) / Ts)
We can solve this system of equations for Ts and T0. One way to do this is to solve for one variable in terms of the other, and then substitute into one of the equations to solve for the remaining variable. Here's one possible method:
1/6 = 1 - (T0 / Ts)
T0 / Ts = 5/6
T0 = (5/6)Ts
1/4 = 1 - ((T0 - 62) / Ts)
(T0 - 62) / Ts = 3/4
T0 - 62 = (3/4)Ts
Substituting T0 = (5/6)Ts into the second equation:
(5/6)Ts - 62 = (3/4)Ts
(1/12)Ts = 62
Ts = 744
Substituting Ts = 744 into T0 = (5/6)Ts:
T0 = (5/6)(744) = 620
Therefore, the initial temperature of the source was 744°F and the initial temperature of the sink was 620°F. When the temperature of the sink was reduced by 62°F, its final temperature was 558°F.
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Community Answer
An engine has an efficiency of 1/6. When the temperature of sink is re...
Option C :
99 degree C
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An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer?
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An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer?.
An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62°C, itsefficiency is doubled. Temperature of the source isa)37°Cb)62°C [2007]c)99°Cd)124°CCorrect answer is option 'C'. Can you explain this answer?.
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