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What is the value of x if log3x + log9x + log27x + log81x  = 25/4?
  • a)
    9
  • b)
    27
  • c)
    81
  • d)
    None of th
Correct answer is option 'B'. Can you explain this answer?
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What is the value of x if log3x + log9x + log27x + log81x = 25/4?a)9b)...
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What is the value of x if log3x + log9x + log27x + log81x = 25/4?a)9b)...
Solution:

The given expression is:

log3x log9x log27x log81x = 25/4

We know that:

loga(b) = logc(b) / logc(a)

Using this property, we can write:

log3x = log9x / log93

log9x = log27x / log93

log27x = log81x / log93

Substituting these values in the given expression, we get:

log9x / log93 + log27x / log93 + log81x / log93 + log3x = 25/4

Simplifying this expression, we get:

log3x (1 + 3 + 9 + 81) = 25/4 log93

log3x (94) = 25/4 (log93)

log3x = 25/4 (log93) / 94

log3x = 25/4 (1/2)

log3x = 25/8

Using the property loga(b) = c, we can write:

3^(25/8) = x

Simplifying this expression, we get:

x = 27

Therefore, the value of x is 27, which is given in option B.
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What is the value of x if log3x + log9x + log27x + log81x = 25/4?a)9b)27c)81d)None of thCorrect answer is option 'B'. Can you explain this answer?
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