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Moment of inertia of a uniform circular disc about a diameter is I. Its moment of inertia about an axis ⊥ to its plane and passing through a point on its rim will be [1990]
  • a)
    5 I
  • b)
    3 I
  • c)
    6 I
  • d)
    4 I
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Moment of inertia of a uniform circular disc about a diameter is I. It...
M.I of uniform circular disc about its diameter = I
According to theorem of perpendiclar axes, M.I. of disc about its axis
Applying theorem of  | | axes,
M.I of disc about the given axis = 2 I + mr2 = 2 I + 4 I = 6 I
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Most Upvoted Answer
Moment of inertia of a uniform circular disc about a diameter is I. It...
Perpendicular to the disc and passing through a point on its rim is given by:

I' = I + md^2

where m is the mass of the disc and d is the distance between the two axes.

To derive this formula, we can use the parallel axis theorem, which states that the moment of inertia of a rigid body about any axis is equal to the moment of inertia about a parallel axis passing through the center of mass plus the product of the mass and the square of the distance between the two axes.

In this case, we can choose the diameter of the disc as the axis passing through the center of mass, so the moment of inertia about this axis is simply I.

To find the moment of inertia about an axis perpendicular to the disc and passing through a point on its rim, we can use the parallel axis theorem with the distance between the two axes equal to the radius of the disc, r. This gives:

I' = I + mr^2

Since the disc is uniform, we can also express its mass in terms of its radius and density, ρ:

m = πr^2ρ

Substituting this into the equation above, we get:

I' = I + πr^2ρr^2

Simplifying this expression yields the final formula:

I' = I + mr^2
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Moment of inertia of a uniform circular disc about a diameter is I. Its moment of inertia about an axis ⊥ to its plane and passing through a point on its rim will be [1990]a)5 Ib)3 Ic)6 Id)4 ICorrect answer is option 'C'. Can you explain this answer?
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