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A reversible engine (modified carnot engine) is shown in figure receives 100kj of heat at 500k and another 40 kj at 400 k. heat is rejected at 300 k the work output?
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A reversible engine (modified carnot engine) is shown in figure receiv...
Reversible Engine Calculation


Given:


  • Heat received at 500K = 100 kJ

  • Heat received at 400K = 40 kJ

  • Heat rejected at 300K



Calculation


The work output of the engine can be calculated using the following formula:


W = QH - QC


where:


  • W is the work output

  • QH is the heat received

  • QC is the heat rejected



First, we need to determine the amount of heat that is transferred to the engine:


Qin = Q1 + Q2 = 100 kJ + 40 kJ = 140 kJ


Next, we need to determine the efficiency of the engine:


e = 1 - TC/TH


where:


  • e is the efficiency of the engine

  • TC is the temperature of the cold reservoir

  • TH is the temperature of the hot reservoir



Using the given temperatures, we can calculate the efficiency:


e = 1 - 300/500 = 0.4


Finally, we can calculate the work output:


W = e * Qin = 0.4 * 140 kJ = 56 kJ


Conclusion


The work output of the engine is 56 kJ.
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A reversible engine (modified carnot engine) is shown in figure receives 100kj of heat at 500k and another 40 kj at 400 k. heat is rejected at 300 k the work output?
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