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A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1?
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A body starting from rest is moving under a constant acceleration upto...
**Solution:**
Given:
- The body starts from rest, so the initial velocity (u) is 0.
- The body moves under a constant acceleration for 20 seconds.
**Using the equation of motion:**
The equation of motion for an object moving with constant acceleration is given by:
**S = ut + 1/2at^2**
Where:
- S is the distance traveled
- u is the initial velocity
- t is the time taken
- a is the constant acceleration
**Calculating S1:**
Given that the body moves S1 distance in the first 10 seconds, we can calculate S1 using the equation of motion:
**S1 = 0 * 10 + 1/2 * a * (10)^2**
**S1 = 50a**
**Calculating S2:**
Given that the body moves S2 distance in the next 10 seconds, we can calculate S2 using the equation of motion:
**S2 = 0 * 10 + 1/2 * a * (10)^2**
**S2 = 100a**
From the above calculations, we can see that S2 is equal to 2 times S1.
Therefore, the correct answer is **b. 2S1**.
**Explanation:**
- The body starts from rest, so the initial velocity is 0.
- The body moves under a constant acceleration for 20 seconds.
- Using the equation of motion, we can calculate the distance traveled in the first 10 seconds (S1) and the next 10 seconds (S2).
- S1 is calculated to be 50a, and S2 is calculated to be 100a.
- S2 is equal to 2 times S1.
- Therefore, the correct answer is b. 2S1.
Given:
- The body starts from rest, so the initial velocity (u) is 0.
- The body moves under a constant acceleration for 20 seconds.
**Using the equation of motion:**
The equation of motion for an object moving with constant acceleration is given by:
**S = ut + 1/2at^2**
Where:
- S is the distance traveled
- u is the initial velocity
- t is the time taken
- a is the constant acceleration
**Calculating S1:**
Given that the body moves S1 distance in the first 10 seconds, we can calculate S1 using the equation of motion:
**S1 = 0 * 10 + 1/2 * a * (10)^2**
**S1 = 50a**
**Calculating S2:**
Given that the body moves S2 distance in the next 10 seconds, we can calculate S2 using the equation of motion:
**S2 = 0 * 10 + 1/2 * a * (10)^2**
**S2 = 100a**
From the above calculations, we can see that S2 is equal to 2 times S1.
Therefore, the correct answer is **b. 2S1**.
**Explanation:**
- The body starts from rest, so the initial velocity is 0.
- The body moves under a constant acceleration for 20 seconds.
- Using the equation of motion, we can calculate the distance traveled in the first 10 seconds (S1) and the next 10 seconds (S2).
- S1 is calculated to be 50a, and S2 is calculated to be 100a.
- S2 is equal to 2 times S1.
- Therefore, the correct answer is b. 2S1.
Community Answer
A body starting from rest is moving under a constant acceleration upto...
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A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1?
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A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1?.
A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starting from rest is moving under a constant acceleration upto 20 sec. If it moves S1 distance in first 10 sec., and S2 distance in next 10 sec. Then S2 will be equal to: a. S1 b. 2S1 c. 3S1 d. 4S1?.
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