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A particle moving in xy plane whose x and y coordinate vary with time, which is given as x=(1-cos 6t) y=sin 6t , find Distance travel by particle in 4 sec ?
Most Upvoted Answer
A particle moving in xy plane whose x and y coordinate vary with time,...
X=(1-cos6t)
Vx = dX /dt= 0-6×-sin6t = 6sin6t

Y= sin6t
Vy = dy/dt=6cos6t

v=√Vx^2+Vy^2 =√6sin6t^2 +√6cos6t^2
v=6√sin6t^2 √cos6t^2 =6×1 =6m/s


dist.= v×t=6×4=24m
Community Answer
A particle moving in xy plane whose x and y coordinate vary with time,...
At time 0 x=0 and y=0 .. then we find velocity by differentiation. Vx= 6 Sin6t and Vy =6 Cos6t.. then V =√Vx^2 +Vy^2.. OK then we get the velocity is 6 m/s. then distance is 6×4 = 24m.. ok.
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A particle moving in xy plane whose x and y coordinate vary with time, which is given as x=(1-cos 6t) y=sin 6t , find Distance travel by particle in 4 sec ?
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