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A single-phase diode B-2 rectifier is fed from a 250 V, 50 Hz source & connected to a load of R = 400 Ω.
Design a capacitor filter such that the ripple factor of the output voltage is less than 5 %. Find the value of the capacitance of the C filter.
Design a capacitor filter such that the ripple factor of the output voltage is less than 5 %. Find the value of the capacitance of the C filter.
- a)156.4 μF
- b)500 μF
- c)189 μF
- d)246 μF
Correct answer is option 'C'. Can you explain this answer?
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A single-phase diode B-2 rectifier is fed from a 250 V, 50 Hz source &...
Use,
C = K * [1 + 1/√2RF] Where, K = 1/4fR.
C = K * [1 + 1/√2RF] Where, K = 1/4fR.
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A single-phase diode B-2 rectifier is fed from a 250 V, 50 Hz source &...
To analyze the operation of the single-phase diode B-2 rectifier, we need to consider the circuit diagram and the characteristics of the diode.
The circuit diagram for a single-phase diode B-2 rectifier is as follows:
AC source (250 V, 50 Hz) -> Transformer -> Diode Bridge Rectifier -> Load
The transformer is used to step down the voltage from the AC source to a suitable level for the diode bridge rectifier. The diode bridge rectifier is made up of four diodes arranged in a bridge configuration.
The characteristics of the diode used in the rectifier are as follows:
1. It is a semiconductor device that allows current to flow in one direction and blocks it in the reverse direction.
2. It has a forward voltage drop of around 0.7 V when conducting.
3. It has a reverse breakdown voltage, beyond which it will breakdown and allow current to flow in the reverse direction.
Now, let's analyze the operation of the rectifier:
1. During the positive half-cycle of the AC input voltage:
- The positive half-cycle of the AC voltage drives the diodes D1 and D4 into forward bias, allowing current to flow through them.
- The diodes D2 and D3 are in reverse bias and do not conduct.
- The current flows through the load in the forward direction, providing power to the load.
2. During the negative half-cycle of the AC input voltage:
- The negative half-cycle of the AC voltage drives the diodes D2 and D3 into forward bias, allowing current to flow through them.
- The diodes D1 and D4 are in reverse bias and do not conduct.
- The current flows through the load in the forward direction, providing power to the load.
Since the diode bridge rectifier conducts current during both half-cycles of the AC input voltage, it provides a full-wave rectification. The output voltage across the load will be the absolute value of the AC input voltage minus the forward voltage drop of the diodes.
In this case, the output voltage across the load will be approximately 250 V - 0.7 V = 249.3 V.
Note: The load will also affect the output voltage, and the actual output voltage may vary depending on the load impedance and other factors.
The circuit diagram for a single-phase diode B-2 rectifier is as follows:
AC source (250 V, 50 Hz) -> Transformer -> Diode Bridge Rectifier -> Load
The transformer is used to step down the voltage from the AC source to a suitable level for the diode bridge rectifier. The diode bridge rectifier is made up of four diodes arranged in a bridge configuration.
The characteristics of the diode used in the rectifier are as follows:
1. It is a semiconductor device that allows current to flow in one direction and blocks it in the reverse direction.
2. It has a forward voltage drop of around 0.7 V when conducting.
3. It has a reverse breakdown voltage, beyond which it will breakdown and allow current to flow in the reverse direction.
Now, let's analyze the operation of the rectifier:
1. During the positive half-cycle of the AC input voltage:
- The positive half-cycle of the AC voltage drives the diodes D1 and D4 into forward bias, allowing current to flow through them.
- The diodes D2 and D3 are in reverse bias and do not conduct.
- The current flows through the load in the forward direction, providing power to the load.
2. During the negative half-cycle of the AC input voltage:
- The negative half-cycle of the AC voltage drives the diodes D2 and D3 into forward bias, allowing current to flow through them.
- The diodes D1 and D4 are in reverse bias and do not conduct.
- The current flows through the load in the forward direction, providing power to the load.
Since the diode bridge rectifier conducts current during both half-cycles of the AC input voltage, it provides a full-wave rectification. The output voltage across the load will be the absolute value of the AC input voltage minus the forward voltage drop of the diodes.
In this case, the output voltage across the load will be approximately 250 V - 0.7 V = 249.3 V.
Note: The load will also affect the output voltage, and the actual output voltage may vary depending on the load impedance and other factors.
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A single-phase diode B-2 rectifier is fed from a 250 V, 50 Hz source & connected to a load of R = 400 Ω.Design a capacitor filter such that the ripple factor of the output voltage is less than 5 %. Find the value of the capacitance of the C filter.a)156.4 μFb)500 μFc)189 μFd)246 μFCorrect answer is option 'C'. Can you explain this answer?
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