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A step-down delta-star transformer, with per-phase turns ratio of 5 is fed from a 3-phase 1100 V, 50 Hz source. The secondary of this transformer is connected through a 3-pulse type rectifier, which is feeding feeding an R load. Find the average value of output voltage.
- a)220 V
- b)257 V
- c)1100/√3 V
- d)206 V
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A step-down delta-star transformer, with per-phase turns ratio of 5 is...
Vph = 1100/5 = 220 V (Transformer ratio = 5)
Vmp = √2 x 220 V
Vo = 3√3/2π x Vmp = (√2 x √3 x 3 x 220)/(2 x π).
Vmp = √2 x 220 V
Vo = 3√3/2π x Vmp = (√2 x √3 x 3 x 220)/(2 x π).
Most Upvoted Answer
A step-down delta-star transformer, with per-phase turns ratio of 5 is...
To find the average value of the output voltage, we need to determine the output voltage waveform and then calculate its average value.
Step 1: Determine the secondary voltage of the transformer:
The secondary voltage of the transformer can be calculated using the turns ratio. The per-phase turns ratio is given as 5, so the secondary voltage will be 5 times the primary voltage.
Secondary voltage = 5 * 1100 V = 5500 V
Step 2: Determine the output voltage waveform:
The rectifier used is a 3-pulse type rectifier. This means that the output waveform will be a pulsating DC waveform with three pulses per cycle. The peak value of the output voltage can be calculated using the secondary voltage of the transformer.
Peak output voltage = Secondary voltage / √3 (for a delta-star transformer)
Peak output voltage = 5500 V / √3 = 3174.52 V
Step 3: Determine the average value of the output voltage:
The average value of a pulsating DC waveform can be calculated using the formula:
Average value = (2 * peak value) / π
Average value = (2 * 3174.52 V) / π ≈ 2022.94 V
Therefore, the average value of the output voltage is approximately 2022.94 V.
None of the given options match the calculated value.
Step 1: Determine the secondary voltage of the transformer:
The secondary voltage of the transformer can be calculated using the turns ratio. The per-phase turns ratio is given as 5, so the secondary voltage will be 5 times the primary voltage.
Secondary voltage = 5 * 1100 V = 5500 V
Step 2: Determine the output voltage waveform:
The rectifier used is a 3-pulse type rectifier. This means that the output waveform will be a pulsating DC waveform with three pulses per cycle. The peak value of the output voltage can be calculated using the secondary voltage of the transformer.
Peak output voltage = Secondary voltage / √3 (for a delta-star transformer)
Peak output voltage = 5500 V / √3 = 3174.52 V
Step 3: Determine the average value of the output voltage:
The average value of a pulsating DC waveform can be calculated using the formula:
Average value = (2 * peak value) / π
Average value = (2 * 3174.52 V) / π ≈ 2022.94 V
Therefore, the average value of the output voltage is approximately 2022.94 V.
None of the given options match the calculated value.
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A step-down delta-star transformer, with per-phase turns ratio of 5 is fed from a 3-phase 1100 V, 50 Hz source. The secondary of this transformer is connected through a 3-pulse type rectifier, which is feeding feeding an R load. Find the average value of output voltage.a)220 Vb)257 Vc)1100/√3 Vd)206 VCorrect answer is option 'B'. Can you explain this answer?
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