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10ml of a solution of NaOH is found to be completely neutralized by 8ml of a given solution of HCl. If we take 20ml of the same solution of NaOH, the amount of HCl solution required to neutralize if will be
- a)4ml
- b)8ml
- c)16ml
- d)32ml
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
10ml of a solution of NaOH is found to be completely neutralized by 8m...
10 ml of NaOH requires 8 ml of HCl for neutralization
20 ml of NaOH will require (8/10)×20 = 16 ml of HCl
20 ml of NaOH will require (8/10)×20 = 16 ml of HCl
Most Upvoted Answer
10ml of a solution of NaOH is found to be completely neutralized by 8m...
Given:
- 10ml of NaOH solution neutralized by 8ml of HCl solution
To find:
- Amount of HCl solution required to neutralize 20ml of NaOH solution
Solution:
The given information tells us that the two solutions are being used in a 1:1 ratio for neutralization. This means that the number of moles of NaOH is equal to the number of moles of HCl.
Moles of NaOH = Moles of HCl
To calculate the moles of NaOH, we can use the formula:
Moles = Volume (in liters) x Concentration (in moles per liter)
Given that 10ml of NaOH solution is neutralized by 8ml of HCl solution, we can assume that the concentration of the HCl solution is the same as the concentration of the NaOH solution.
Moles of NaOH = 10ml x Concentration of NaOH
Moles of HCl = 8ml x Concentration of NaOH
Since the moles are equal, we can set up the following equation:
10ml x Concentration of NaOH = 8ml x Concentration of HCl
Now, we can use this equation to find the concentration of the NaOH solution.
Concentration of NaOH = (8ml x Concentration of HCl) / 10ml
Since the concentration of the HCl solution is the same as the concentration of the NaOH solution, we can substitute it in the equation:
Concentration of NaOH = (8ml x Concentration of NaOH) / 10ml
Simplifying the equation:
Concentration of NaOH = 0.8 x Concentration of NaOH
This implies that the concentration of NaOH = 0.8
Now, let's calculate the amount of HCl solution required to neutralize 20ml of NaOH solution.
Moles of NaOH = 20ml x 0.8
Moles of HCl = x ml x 0.8 (where x is the amount of HCl solution required)
Since the moles are equal, we can set up the following equation:
20ml x 0.8 = x ml x 0.8
Simplifying the equation:
16 = x
Therefore, the amount of HCl solution required to neutralize 20ml of NaOH solution is 16ml.
Hence, the correct answer is option C) 16ml.
- 10ml of NaOH solution neutralized by 8ml of HCl solution
To find:
- Amount of HCl solution required to neutralize 20ml of NaOH solution
Solution:
The given information tells us that the two solutions are being used in a 1:1 ratio for neutralization. This means that the number of moles of NaOH is equal to the number of moles of HCl.
Moles of NaOH = Moles of HCl
To calculate the moles of NaOH, we can use the formula:
Moles = Volume (in liters) x Concentration (in moles per liter)
Given that 10ml of NaOH solution is neutralized by 8ml of HCl solution, we can assume that the concentration of the HCl solution is the same as the concentration of the NaOH solution.
Moles of NaOH = 10ml x Concentration of NaOH
Moles of HCl = 8ml x Concentration of NaOH
Since the moles are equal, we can set up the following equation:
10ml x Concentration of NaOH = 8ml x Concentration of HCl
Now, we can use this equation to find the concentration of the NaOH solution.
Concentration of NaOH = (8ml x Concentration of HCl) / 10ml
Since the concentration of the HCl solution is the same as the concentration of the NaOH solution, we can substitute it in the equation:
Concentration of NaOH = (8ml x Concentration of NaOH) / 10ml
Simplifying the equation:
Concentration of NaOH = 0.8 x Concentration of NaOH
This implies that the concentration of NaOH = 0.8
Now, let's calculate the amount of HCl solution required to neutralize 20ml of NaOH solution.
Moles of NaOH = 20ml x 0.8
Moles of HCl = x ml x 0.8 (where x is the amount of HCl solution required)
Since the moles are equal, we can set up the following equation:
20ml x 0.8 = x ml x 0.8
Simplifying the equation:
16 = x
Therefore, the amount of HCl solution required to neutralize 20ml of NaOH solution is 16ml.
Hence, the correct answer is option C) 16ml.
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