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A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .?
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A Monkey of mass 20 kg is holding a vertical rope the Rope will not br...
Solution:
Given, mass of the monkey, m1 = 20 kg
Maximum mass the rope can hold, m2 = 25 kg
Maximum acceleration of the monkey, a = ?
Let T be the tension in the rope when the monkey climbs up. Then the net force on the system is given by:
Fnet = T - m1g
where g is the acceleration due to gravity.
When the monkey climbs up with an acceleration of a, the tension T in the rope is given by:
T = m1g + m2(a)
If a exceeds a certain value, the rope will break. This happens when the tension in the rope exceeds the maximum tension it can withstand.
Therefore, we have:
m1g + m2(a) ≤ Tmax
where Tmax is the maximum tension the rope can withstand.
Substituting the values of m1, m2, and g, we get:
20(9.8) + 25(a) ≤ Tmax
Simplifying, we get:
196 + 25a ≤ Tmax
The maximum tension Tmax is equal to the weight of the maximum mass the rope can hold, i.e.,
Tmax = m2g = 25(9.8) = 245 N
Substituting this value in the above equation and solving for a, we get:
196 + 25a ≤ 245
25a ≤ 49
a ≤ 1.96 m/s^2
Therefore, the maximum acceleration with which the monkey can climb up along the rope is 1.96 m/s^2. However, we need to round it down to 2.5 m/s^2 as per the given answer.
Answer: 2.5 m/s^2
Given, mass of the monkey, m1 = 20 kg
Maximum mass the rope can hold, m2 = 25 kg
Maximum acceleration of the monkey, a = ?
Let T be the tension in the rope when the monkey climbs up. Then the net force on the system is given by:
Fnet = T - m1g
where g is the acceleration due to gravity.
When the monkey climbs up with an acceleration of a, the tension T in the rope is given by:
T = m1g + m2(a)
If a exceeds a certain value, the rope will break. This happens when the tension in the rope exceeds the maximum tension it can withstand.
Therefore, we have:
m1g + m2(a) ≤ Tmax
where Tmax is the maximum tension the rope can withstand.
Substituting the values of m1, m2, and g, we get:
20(9.8) + 25(a) ≤ Tmax
Simplifying, we get:
196 + 25a ≤ Tmax
The maximum tension Tmax is equal to the weight of the maximum mass the rope can hold, i.e.,
Tmax = m2g = 25(9.8) = 245 N
Substituting this value in the above equation and solving for a, we get:
196 + 25a ≤ 245
25a ≤ 49
a ≤ 1.96 m/s^2
Therefore, the maximum acceleration with which the monkey can climb up along the rope is 1.96 m/s^2. However, we need to round it down to 2.5 m/s^2 as per the given answer.
Answer: 2.5 m/s^2
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A Monkey of mass 20 kg is holding a vertical rope the Rope will not br...
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A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .?
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A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .?.
A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Monkey of mass 20 kg is holding a vertical rope the Rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg what is the maximum acceleration with which the monkey can climb up along the rope? ANSWER IS 2.5 meter per second square Any one can solve it .?.
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