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A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump?
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A stuntman plan to run along a roof top and then horizontal off it to ...
Time taken for travelling vertical distance of 4.9 m with zero initial velocity = √(2h/g) =√2 x 4.9/9.8 = 1 sec. In this time, distance travelled with horizontal velocity v should be at least 6.2 m. Thus minimum velocity v is v x 1 = 6.2 or v = 6.2 m/s.
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A stuntman plan to run along a roof top and then horizontal off it to ...
Analysis:
To solve this problem, we need to consider the horizontal and vertical distances that the stuntman needs to cover. The horizontal distance is 6.2 meters, and the vertical distance is 4.9 meters.
Horizontal Distance:
To cover a horizontal distance of 6.2 meters, the stuntman needs to have a certain horizontal velocity. We can calculate this velocity using the formula:
Velocity = Distance / Time
Since the time taken to cover the horizontal distance is not given, we can assume that it is the same as the time taken to cover the vertical distance. Therefore, we can rewrite the formula as:
Velocity = 6.2 / Time ………..(1)
Vertical Distance:
To cover a vertical distance of 4.9 meters, the stuntman needs to have a certain vertical velocity. We can calculate this velocity using the formula:
Velocity = Distance / Time
Since the time taken to cover the vertical distance is the same as the time taken to cover the horizontal distance (as assumed earlier), we can rewrite the formula as:
Velocity = 4.9 / Time ………..(2)
Total Velocity:
Now, to successfully make the jump, the stuntman needs to have enough velocity to cover both the horizontal and vertical distances. Since the two velocities are perpendicular to each other, we can use the Pythagorean theorem to find the total velocity. The Pythagorean theorem states that:
Total Velocity = √(Velocity₁² + Velocity₂²)
Substituting the values of velocity₁ and velocity₂ from equations (1) and (2) respectively, we get:
Total Velocity = √((6.2 / Time)² + (4.9 / Time)²)
To find the minimum roof top speed, we need to find the maximum value of the total velocity. To do this, we can take the derivative of the total velocity equation with respect to time and set it equal to zero. This will give us the time at which the total velocity is maximum. We can then substitute this time back into the total velocity equation to find the maximum velocity.
Conclusion:
By calculating the maximum velocity using the above method, we can determine the minimum roof top speed in meters per second that the stuntman needs to successfully make the jump from one roof to another.
To solve this problem, we need to consider the horizontal and vertical distances that the stuntman needs to cover. The horizontal distance is 6.2 meters, and the vertical distance is 4.9 meters.
Horizontal Distance:
To cover a horizontal distance of 6.2 meters, the stuntman needs to have a certain horizontal velocity. We can calculate this velocity using the formula:
Velocity = Distance / Time
Since the time taken to cover the horizontal distance is not given, we can assume that it is the same as the time taken to cover the vertical distance. Therefore, we can rewrite the formula as:
Velocity = 6.2 / Time ………..(1)
Vertical Distance:
To cover a vertical distance of 4.9 meters, the stuntman needs to have a certain vertical velocity. We can calculate this velocity using the formula:
Velocity = Distance / Time
Since the time taken to cover the vertical distance is the same as the time taken to cover the horizontal distance (as assumed earlier), we can rewrite the formula as:
Velocity = 4.9 / Time ………..(2)
Total Velocity:
Now, to successfully make the jump, the stuntman needs to have enough velocity to cover both the horizontal and vertical distances. Since the two velocities are perpendicular to each other, we can use the Pythagorean theorem to find the total velocity. The Pythagorean theorem states that:
Total Velocity = √(Velocity₁² + Velocity₂²)
Substituting the values of velocity₁ and velocity₂ from equations (1) and (2) respectively, we get:
Total Velocity = √((6.2 / Time)² + (4.9 / Time)²)
To find the minimum roof top speed, we need to find the maximum value of the total velocity. To do this, we can take the derivative of the total velocity equation with respect to time and set it equal to zero. This will give us the time at which the total velocity is maximum. We can then substitute this time back into the total velocity equation to find the maximum velocity.
Conclusion:
By calculating the maximum velocity using the above method, we can determine the minimum roof top speed in meters per second that the stuntman needs to successfully make the jump from one roof to another.
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A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump?
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A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump?.
A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stuntman plan to run along a roof top and then horizontal off it to the land on the roof of the next building the roof of the next building is 4.9 metres below the first one and 6.2 metres away from it what should be the minimum roof top speed in metre per second so that he can run successfully make the jump?.
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