The given problem involves two bodies of masses m1 and M2 connected by a light string passing over a frictionless and massless pulley. The pulley is moving upward with uniform acceleration g/2. We need to determine the tension in the string.

Let's break down the problem step-by-step:

1. Identify the forces acting on each body:
- Body with mass m1: gravitational force (mg) and tension in the string (T)
- Body with mass M2: gravitational force (Mg) and tension in the string (T)

2. Apply Newton's second law of motion to each body:
- Body with mass m1: m1a = T - m1g, where a is the acceleration of m1
- Body with mass M2: M2a = Mg - T, where a is the acceleration of M2

3. Determine the acceleration of each body:
- Since the pulley is moving upward with uniform acceleration g/2, the accelerations of the bodies are related as follows:
a = 2(g/2) = g

4. Solve the system of equations:
- Substitute the value of acceleration (a = g) in the equations obtained from Newton's second law.
- m1g + T = m1g + m1g
- T - Mg = Mg - m2g

5. Simplify the equations:
- m1g + T = 2m1g
- T - Mg = Mg - m2g

6. Solve for Tension (T):
- From the first equation, we find T = m1g
- Substituting this value in the second equation, we get m1g - Mg = Mg - m2g
- Simplifying further, we find m1g + m2g = 2Mg
- Therefore, m1 + m2 = 2M
- T = (2M)g / (m1 + m2)

Thus, the tension in the string is given by T = (2M)g / (m1 + m2).

In conclusion, when two bodies of masses m1 and M2 are connected by a light string passing over a frictionless and massless pulley, and the pulley is moving upward with uniform acceleration g/2, the tension in the string is given by the formula mentioned above.

A=f/m
a=g/2
g/2=t/m1+m2
t=g(m1+m2)/2