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If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is?
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If 240 ml of gas X diffuse through a porous membrane in 20 minutes whe...
The molar mass of gas X can be determined by using the Graham's Law of Diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Graham's Law of Diffusion:
Rate1/Rate2 = √(Molar Mass2/Molar Mass1)
In this case, we are given that gas X diffuses through a porous membrane in 20 minutes, and the same volume of methane diffuses in 10 minutes at the same temperature and pressure. We can set up the equation as follows:
Rate of gas X / Rate of methane = √(Molar Mass of methane / Molar Mass of gas X)
Solving for the molar mass of gas X:
Step 1: Calculate the ratio of diffusion rates
Rate of gas X / Rate of methane = 20 minutes / 10 minutes = 2
Step 2: Square both sides of the equation
(2)^2 = (Molar Mass of methane / Molar Mass of gas X)
Step 3: Simplify the equation
4 = (Molar Mass of methane / Molar Mass of gas X)
Step 4: Rearrange the equation to solve for the molar mass of gas X
Molar Mass of gas X = Molar Mass of methane / 4
Conclusion:
The molar mass of gas X is equal to one-fourth of the molar mass of methane.
Note: The molar mass of methane (CH4) is approximately 16 g/mol. Therefore, the molar mass of gas X can be calculated as 16 g/mol / 4 = 4 g/mol.
Graham's Law of Diffusion:
Rate1/Rate2 = √(Molar Mass2/Molar Mass1)
In this case, we are given that gas X diffuses through a porous membrane in 20 minutes, and the same volume of methane diffuses in 10 minutes at the same temperature and pressure. We can set up the equation as follows:
Rate of gas X / Rate of methane = √(Molar Mass of methane / Molar Mass of gas X)
Solving for the molar mass of gas X:
Step 1: Calculate the ratio of diffusion rates
Rate of gas X / Rate of methane = 20 minutes / 10 minutes = 2
Step 2: Square both sides of the equation
(2)^2 = (Molar Mass of methane / Molar Mass of gas X)
Step 3: Simplify the equation
4 = (Molar Mass of methane / Molar Mass of gas X)
Step 4: Rearrange the equation to solve for the molar mass of gas X
Molar Mass of gas X = Molar Mass of methane / 4
Conclusion:
The molar mass of gas X is equal to one-fourth of the molar mass of methane.
Note: The molar mass of methane (CH4) is approximately 16 g/mol. Therefore, the molar mass of gas X can be calculated as 16 g/mol / 4 = 4 g/mol.
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If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is?
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If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is?.
If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 240 ml of gas X diffuse through a porous membrane in 20 minutes where is the same volume of Methane diffuses in 10 minutes at same temperature and pressure the molar mass in gram per mole of gas X is?.
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