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A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ?
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A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3...
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A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3...
Given:
- Mass of bomb: 1 kg
- Mass ratio of parts after explosion: 1:1:3
- Velocity of two parts with equal mass: 30 m/s
Calculations:
Step 1: Finding mass of each part after explosion
- Total mass of bomb = 1 kg
- Mass ratio = 1:1:3
- Let the masses of the parts be x, x, and 3x respectively
- x + x + 3x = 1 kg
- 5x = 1 kg
- x = 0.2 kg
- Masses of the three parts: 0.2 kg, 0.2 kg, and 0.6 kg
Step 2: Finding momentum of the two parts with equal mass
- Momentum = mass * velocity
- Momentum of two parts with 0.2 kg mass each: 0.2 kg * 30 m/s = 6 kg m/s (each)
Step 3: Finding momentum of the bigger part
- Momentum is a vector quantity, so we need to consider direction
- The two parts with 0.2 kg mass are moving perpendicular to each other
- The momentum of the bigger part (0.6 kg) can be calculated using vector addition
- Let the velocity of the bigger part be v m/s
- Total momentum in the x-direction = 6 kg m/s (from the 0.2 kg parts)
- Total momentum in the y-direction = 0 (as they are moving perpendicular)
- Total momentum = sqrt((6)^2 + (6)^2) = 8.49 kg m/s
Step 4: Finding velocity of the bigger part
- Momentum of the bigger part = 0.6 kg * v
- 0.6 kg * v = 8.49 kg m/s
- v = 14.15 m/s
Conclusion:
Therefore, the velocity of the bigger part after the explosion is 14.15 m/s.
- Mass of bomb: 1 kg
- Mass ratio of parts after explosion: 1:1:3
- Velocity of two parts with equal mass: 30 m/s
Calculations:
Step 1: Finding mass of each part after explosion
- Total mass of bomb = 1 kg
- Mass ratio = 1:1:3
- Let the masses of the parts be x, x, and 3x respectively
- x + x + 3x = 1 kg
- 5x = 1 kg
- x = 0.2 kg
- Masses of the three parts: 0.2 kg, 0.2 kg, and 0.6 kg
Step 2: Finding momentum of the two parts with equal mass
- Momentum = mass * velocity
- Momentum of two parts with 0.2 kg mass each: 0.2 kg * 30 m/s = 6 kg m/s (each)
Step 3: Finding momentum of the bigger part
- Momentum is a vector quantity, so we need to consider direction
- The two parts with 0.2 kg mass are moving perpendicular to each other
- The momentum of the bigger part (0.6 kg) can be calculated using vector addition
- Let the velocity of the bigger part be v m/s
- Total momentum in the x-direction = 6 kg m/s (from the 0.2 kg parts)
- Total momentum in the y-direction = 0 (as they are moving perpendicular)
- Total momentum = sqrt((6)^2 + (6)^2) = 8.49 kg m/s
Step 4: Finding velocity of the bigger part
- Momentum of the bigger part = 0.6 kg * v
- 0.6 kg * v = 8.49 kg m/s
- v = 14.15 m/s
Conclusion:
Therefore, the velocity of the bigger part after the explosion is 14.15 m/s.
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A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ?
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A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ?.
A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be ?.
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