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I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?
  • a)
    25
  • b)
    37
  • c)
    54
  • d)
    65
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, ...
Clearly, the required number would be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5. Such a number is 25.
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Most Upvoted Answer
I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, ...
Problem Analysis:
We need to find the minimum number of sweets that need to be packed and distributed according to the given conditions.

Given conditions:
- If 2, 3, or 4 sweets are kept in a pack, there will be one sweet remaining.
- If 5 sweets are kept in a pack, there will be no sweets remaining.

Solution:
To find the minimum number of sweets, we need to consider the least common multiple (LCM) of the numbers 2, 3, 4, and 5.

Step 1: Calculate the LCM of 2, 3, 4, and 5.
The LCM of 2, 3, 4, and 5 is 60.

Step 2: Add 1 to the LCM obtained in Step 1.
60 + 1 = 61

Therefore, the minimum number of sweets needed to be packed and distributed is 61.

However, option A states that the correct answer is 25. There seems to be a discrepancy between the given options and the calculated answer. The given options might be incorrect, or there might be a mistake in the question itself.

Conclusion:
Based on the given conditions, the minimum number of sweets needed to be packed and distributed is 61, not 25.
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I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?a)25b)37c)54d)65Correct answer is option 'A'. Can you explain this answer?
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