A school’s annual budget for the purchase of student computers i...
Let’s denote the formula for the money spent on computers as pq = b, where
p = price of computers
q = quantity of computers
b = budget
We can solve a percent question that doesn’t involve actual values by using smart numbers. Let’s assign a smart number of 1000 to last year’s computer budget (b) and a smart number 100 to last year’s computer price (p). 1000 and 100 are easy numbers to take a percent of.
This year’s budget will equal 1000 × 1.6 = 1600
This year’s computer price will equal 100 × 1.2 = 120
Now we can calculate the number of computers purchased each year, q = b/p
Number of computers purchased last year = 1000/100 = 10
Number of computers purchased this year = 1600/120 = 13 1/3 (while 1/3 of a computer doesn’t make sense it won’t affect the calculation)
The question is asking for the percent increase in quantity from last year to this year =
This question could also have been solved algebraically by converting the percent increases into fractions.
Last year: pq = b, so q = b/p
This year: (6/5)(p)(x) = (8/5)b
If we solve for x (this year's quantity), we get x = (8/5)(5/6)b/p or (4/3)b/p
If this year's quantity is 4/3 of last year's quantity (b/p), this represents a 33 1/3% increase.
The correct answer is A
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A school’s annual budget for the purchase of student computers i...
A school is an educational institution where students go to learn and acquire knowledge. It is typically divided into different levels, such as elementary, middle, and high school, and offers a structured curriculum designed to meet the academic, social, and emotional needs of students.
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Schools may vary in size, structure, and educational approach, with some focusing on specific areas such as science, technology, engineering, and mathematics (STEM), while others emphasize arts or vocational training. However, their core purpose remains the same: to provide a quality education and empower students with the knowledge and skills they need to succeed in life.
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